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Groups > comp.lang.python > #8402 > unrolled thread
| Started by | Harold <dadapapa@googlemail.com> |
|---|---|
| First post | 2011-06-24 13:05 -0700 |
| Last post | 2011-06-24 18:50 -0700 |
| Articles | 20 on this page of 22 — 10 participants |
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Significant figures calculation Harold <dadapapa@googlemail.com> - 2011-06-24 13:05 -0700
Re: Significant figures calculation Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-06-24 20:46 +0000
Re: Significant figures calculation Jerry Hill <malaclypse2@gmail.com> - 2011-06-24 16:58 -0400
Re: Significant figures calculation steve+comp.lang.python@pearwood.info - 2011-06-25 10:31 +1000
Re: Significant figures calculation Chris Torek <nospam@torek.net> - 2011-06-25 19:04 +0000
Re: Significant figures calculation Harold <dadapapa@googlemail.com> - 2011-06-26 08:35 -0700
Re: Significant figures calculation Dave Angel <davea@ieee.org> - 2011-06-27 08:04 -0400
Re: Significant figures calculation Harold <dadapapa@googlemail.com> - 2011-06-27 06:40 -0700
Re: Significant figures calculation Ethan Furman <ethan@stoneleaf.us> - 2011-06-27 13:53 -0700
Re: Significant figures calculation Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-06-28 12:56 +1000
Re: Significant figures calculation Chris Angelico <rosuav@gmail.com> - 2011-06-28 13:16 +1000
Re: Significant figures calculation Erik Max Francis <max@alcyone.com> - 2011-06-27 20:45 -0700
Re: Significant figures calculation Mel <mwilson@the-wire.com> - 2011-06-28 07:47 -0400
Re: Significant figures calculation Chris Angelico <rosuav@gmail.com> - 2011-06-28 21:57 +1000
Re: Significant figures calculation Erik Max Francis <max@alcyone.com> - 2011-06-28 11:54 -0700
Re: Significant figures calculation Mel <mwilson@the-wire.com> - 2011-06-28 16:47 -0400
Re: Significant figures calculation Erik Max Francis <max@alcyone.com> - 2011-06-28 14:01 -0700
Re: Significant figures calculation Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-06-28 18:35 +1000
Re: Significant figures calculation Erik Max Francis <max@alcyone.com> - 2011-06-28 11:59 -0700
Re: Significant figures calculation Erik Max Francis <max@alcyone.com> - 2011-06-27 20:49 -0700
Re: Significant figures calculation Ethan Furman <ethan@stoneleaf.us> - 2011-06-27 15:58 -0700
Re: Significant figures calculation Harold <dadapapa@googlemail.com> - 2011-06-24 18:50 -0700
Page 1 of 2 [1] 2 Next page →
| From | Harold <dadapapa@googlemail.com> |
|---|---|
| Date | 2011-06-24 13:05 -0700 |
| Subject | Significant figures calculation |
| Message-ID | <10b8388e-76fc-4a93-aeff-676cdb3d1d12@5g2000yqb.googlegroups.com> |
Hi,
I am looking for an easy way to do significant figure calculations in
python (which I want to use with a class that does unit calculations).
Significant figure calculations should have the semantics explained,
e.g., here: http://chemistry.about.com/od/mathsciencefundamentals/a/sigfigures.htm
My hope was that the decimal module would provide this functionality,
but:
>>> print Decimal('32.01') + Decimal(5.325) + Decimal('12')
49.335 # instead of 49
>>> print Decimal('25.624') / Decimal('25')
1.02496 # instead of 1.0
>>> print Decimal('1.2') == Decimal('1.23')
False # actually not sure how the semantics should be
I tried to modify the DecimalContext (e.g. getcontext().prec = 2) but
that did not lead to the correct behavior. Google and this list didn't
yield a good answer yet... so I'd be happy to get a good
recommendations or pointers.
P.S. I am aware that significant figure calculation is controversial
and makes implicit assumptions on the probability distributions of the
variables. I am simply looking for an implementation of the (well
defined) arithmetics as defined on the cited website.
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| From | Steven D'Aprano <steve+comp.lang.python@pearwood.info> |
|---|---|
| Date | 2011-06-24 20:46 +0000 |
| Message-ID | <4e04f793$0$29975$c3e8da3$5496439d@news.astraweb.com> |
| In reply to | #8402 |
On Fri, 24 Jun 2011 13:05:41 -0700, Harold wrote:
> Hi,
>
> I am looking for an easy way to do significant figure calculations in
> python (which I want to use with a class that does unit calculations).
> Significant figure calculations should have the semantics explained,
> e.g., here:
> http://chemistry.about.com/od/mathsciencefundamentals/a/sigfigures.htm
>
> My hope was that the decimal module would provide this functionality,
> but:
>
>>>> print Decimal('32.01') + Decimal(5.325) + Decimal('12')
> 49.335 # instead of 49
>>>> print Decimal('25.624') / Decimal('25')
> 1.02496 # instead of 1.0
>>>> print Decimal('1.2') == Decimal('1.23')
> False # actually not sure how the semantics should be
>
> I tried to modify the DecimalContext (e.g. getcontext().prec = 2) but
> that did not lead to the correct behavior.
Really? It works for me.
>>> import decimal
>>> D = decimal.Decimal
>>> decimal.getcontext().prec = 2
>>>
>>> D('32.01') + D('5.325') + D('12')
Decimal('49')
>>>
>>> D('25.624') / D('25')
Decimal('1.0')
The only thing you have to watch out for is this:
>>> D('1.2') == D('1.23') # no rounding
False
>>> D('1.2') == +D('1.23') # force rounding
True
--
Steven
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| From | Jerry Hill <malaclypse2@gmail.com> |
|---|---|
| Date | 2011-06-24 16:58 -0400 |
| Message-ID | <mailman.386.1308949143.1164.python-list@python.org> |
| In reply to | #8406 |
On Fri, Jun 24, 2011 at 4:46 PM, Steven D'Aprano
<steve+comp.lang.python@pearwood.info> wrote:
> Really? It works for me.
>
>>>> import decimal
>>>> D = decimal.Decimal
>>>> decimal.getcontext().prec = 2
>>>>
>>>> D('32.01') + D('5.325') + D('12')
> Decimal('49')
I'm curious. Is there a way to get the number of significant digits
for a particular Decimal instance? I spent a few minutes browsing
through the docs, and didn't see anything obvious. I was thinking
about setting the precision dynamically within a function, based on
the significance of the inputs.
--
Jerry
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| From | steve+comp.lang.python@pearwood.info |
|---|---|
| Date | 2011-06-25 10:31 +1000 |
| Message-ID | <4e052c77$0$29979$c3e8da3$5496439d@news.astraweb.com> |
| In reply to | #8407 |
Jerry Hill wrote:
> I'm curious. Is there a way to get the number of significant digits
> for a particular Decimal instance? I spent a few minutes browsing
> through the docs, and didn't see anything obvious. I was thinking
> about setting the precision dynamically within a function, based on
> the significance of the inputs.
Not officially, so far as I know, but if you're willing to risk using a
private implementation detail that is subject to change:
>>> decimal.Decimal('000123.45000')._int
'12345000'
However, sometimes you may need to inspect the exponent as well:
>>> zero = decimal.Decimal('0.00000000')
>>> zero._int
'0'
>>> zero._exp
-8
--
Steven
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| From | Chris Torek <nospam@torek.net> |
|---|---|
| Date | 2011-06-25 19:04 +0000 |
| Message-ID | <iu5bgk01v0@news2.newsguy.com> |
| In reply to | #8407 |
In article <mailman.386.1308949143.1164.python-list@python.org>
Jerry Hill <malaclypse2@gmail.com> wrote:
>I'm curious. Is there a way to get the number of significant digits
>for a particular Decimal instance?
Yes:
def sigdig(x):
"return the number of significant digits in x"
return len(x.as_tuple()[1])
import decimal
D = decimal.Decimal
for x in (
'1',
'1.00',
'1.23400e-8',
'0.003'
):
print 'sigdig(%s): %d' % (x, sigdig(D(x)))
--
In-Real-Life: Chris Torek, Wind River Systems
Intel require I note that my opinions are not those of WRS or Intel
Salt Lake City, UT, USA (40°39.22'N, 111°50.29'W) +1 801 277 2603
email: gmail (figure it out) http://web.torek.net/torek/index.html
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| From | Harold <dadapapa@googlemail.com> |
|---|---|
| Date | 2011-06-26 08:35 -0700 |
| Message-ID | <02a78be2-2c11-4068-81a3-cd8744e8eaf2@y30g2000vbu.googlegroups.com> |
| In reply to | #8451 |
> >I'm curious. Is there a way to get the number of significant digits > >for a particular Decimal instance? > > Yes: > > def sigdig(x): > "return the number of significant digits in x" > return len(x.as_tuple()[1]) Great! that's exactly what I needed. thanks Chris!
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| From | Dave Angel <davea@ieee.org> |
|---|---|
| Date | 2011-06-27 08:04 -0400 |
| Message-ID | <mailman.445.1309176278.1164.python-list@python.org> |
| In reply to | #8468 |
(You top-posted your reply, instead of writing your response following the part you were quoting) On 01/-10/-28163 02:59 PM, Lalitha Prasad K wrote: > In numerical analysis there is this concept of machine zero, which is > computed like this: > > e=1.0 > while 1.0+e> 1.0: > e=e/2.0 > print e > > The number e will give you the precision of floating point numbers. > > Lalitha Prasad > That particular algorithm is designed for binary floating point. The OP was asking about Decimal instances. So you'd want to divide by 10.0 each time. And of course you'd want to do it with Decimal objects. > On Sun, Jun 26, 2011 at 9:05 PM, Harold<dadapapa@googlemail.com> wrote: > >>>> I'm curious. Is there a way to get the number of significant digits >>>> for a particular Decimal instance? DaveA
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| From | Harold <dadapapa@googlemail.com> |
|---|---|
| Date | 2011-06-27 06:40 -0700 |
| Message-ID | <db874e1f-a827-459c-aa22-5b915e70b682@a11g2000yqm.googlegroups.com> |
| In reply to | #8451 |
On Jun 25, 9:04 pm, Chris Torek <nos...@torek.net> wrote:
> >I'm curious. Is there a way to get the number of significant digits
> >for a particular Decimal instance?
>
> Yes:
>
> def sigdig(x):
> "return the number of significant digits in x"
> return len(x.as_tuple()[1])
Great, Chris, this is (almost) exactly what I needed.
To make it work for numbers like 1200, that have four digits but only
two of them being significant, I changed your snippet to the
following:
class Empirical(Decimal) :
@property
def significance(self) :
t = self.as_tuple()
if t[2] < 0 :
return len(t[1])
else :
return len(''.join(map(str,t[1])).rstrip('0'))
>>> Empirical('1200.').significance
2
>>> Empirical('1200.0').significance
5
now it's only about overriding the numerical operators :)
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| From | Ethan Furman <ethan@stoneleaf.us> |
|---|---|
| Date | 2011-06-27 13:53 -0700 |
| Message-ID | <mailman.463.1309207197.1164.python-list@python.org> |
| In reply to | #8506 |
Harold wrote:
> On Jun 25, 9:04 pm, Chris Torek <nos...@torek.net> wrote:
>>> I'm curious. Is there a way to get the number of significant digits
>>> for a particular Decimal instance?
>> Yes:
>>
>> def sigdig(x):
>> "return the number of significant digits in x"
>> return len(x.as_tuple()[1])
>
> Great, Chris, this is (almost) exactly what I needed.
> To make it work for numbers like 1200, that have four digits but only
> two of them being significant, I changed your snippet to the
> following:
>
> class Empirical(Decimal) :
> @property
> def significance(self) :
> t = self.as_tuple()
> if t[2] < 0 :
> return len(t[1])
> else :
> return len(''.join(map(str,t[1])).rstrip('0'))
>
>
>>>> Empirical('1200.').significance
> 2
>>>> Empirical('1200.0').significance
> 5
What about when 1200 is actually 4 significant digits? Or 3?
~Ethan~
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| From | Steven D'Aprano <steve+comp.lang.python@pearwood.info> |
|---|---|
| Date | 2011-06-28 12:56 +1000 |
| Message-ID | <4e0942d1$0$29987$c3e8da3$5496439d@news.astraweb.com> |
| In reply to | #8514 |
On Tue, 28 Jun 2011 06:53 am Ethan Furman wrote:
> Harold wrote:
[...]
>>>>> Empirical('1200.').significance
>> 2
Well, that's completely wrong. It should be 4.
>>>>> Empirical('1200.0').significance
>> 5
>
> What about when 1200 is actually 4 significant digits? Or 3?
Then you shouldn't write it as 1200.0. By definition, zeros on the right are
significant. If you don't want zeroes on the right to count, you have to
not show them.
Five sig figures: 1200.0
Four sig figures: 1200
Three sig figures: 1.20e3
Two sig figures: 1.2e3
One sig figure: 1e3
Zero sig figure: 0
--
Steven
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| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2011-06-28 13:16 +1000 |
| Message-ID | <mailman.466.1309231012.1164.python-list@python.org> |
| In reply to | #8518 |
On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano <steve+comp.lang.python@pearwood.info> wrote: > Zero sig figure: 0 > Is 0.0 one sig fig or two? (Just vaguely curious. Also curious as to whether a zero sig figures value is ever useful.) ChrisA
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| From | Erik Max Francis <max@alcyone.com> |
|---|---|
| Date | 2011-06-27 20:45 -0700 |
| Message-ID | <pfSdnd1Y2YLS05TTnZ2dnUVZ5hidnZ2d@giganews.com> |
| In reply to | #8519 |
Chris Angelico wrote:
> On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano
> <steve+comp.lang.python@pearwood.info> wrote:
>> Zero sig figure: 0
That's not really zero significant figures; without further
qualification, it's one.
> Is 0.0 one sig fig or two?
Two.
> (Just vaguely curious. Also curious as to
> whether a zero sig figures value is ever useful.)
Yes. They're order of magnitude estimates. 1 x 10^6 has one
significant figure. 10^6 has zero.
--
Erik Max Francis && max@alcyone.com && http://www.alcyone.com/max/
San Jose, CA, USA && 37 18 N 121 57 W && AIM/Y!M/Skype erikmaxfrancis
I would have liked to have seen Montana.
-- Cpt. Vasily Borodin
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| From | Mel <mwilson@the-wire.com> |
|---|---|
| Date | 2011-06-28 07:47 -0400 |
| Message-ID | <iucf07$au9$1@speranza.aioe.org> |
| In reply to | #8520 |
Erik Max Francis wrote: > Chris Angelico wrote: >> On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano >> <steve+comp.lang.python@pearwood.info> wrote: >>> Zero sig figure: 0 > > That's not really zero significant figures; without further > qualification, it's one. > >> Is 0.0 one sig fig or two? > > Two. > >> (Just vaguely curious. Also curious as to >> whether a zero sig figures value is ever useful.) > > Yes. They're order of magnitude estimates. 1 x 10^6 has one > significant figure. 10^6 has zero. By convention, nobody ever talks about 1 x 9.97^6 . Mel.
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| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2011-06-28 21:57 +1000 |
| Message-ID | <mailman.477.1309262241.1164.python-list@python.org> |
| In reply to | #8533 |
On Tue, Jun 28, 2011 at 9:47 PM, Mel <mwilson@the-wire.com> wrote: > > By convention, nobody ever talks about 1 x 9.97^6 . Unless you're a British politician of indeterminate party allegiance.... famous line, quoted as #6 in here: http://www.telegraph.co.uk/culture/tvandradio/7309332/The-ten-funniest-ever-Yes-Minister-moments.html But, that would presumably have three sig figs. ChrisA
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| From | Erik Max Francis <max@alcyone.com> |
|---|---|
| Date | 2011-06-28 11:54 -0700 |
| Message-ID | <TPidnZ-9RtbOvpfTnZ2dnUVZ5r-dnZ2d@giganews.com> |
| In reply to | #8533 |
Mel wrote:
> Erik Max Francis wrote:
>
>> Chris Angelico wrote:
>>> On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano
>>> <steve+comp.lang.python@pearwood.info> wrote:
>>>> Zero sig figure: 0
>> That's not really zero significant figures; without further
>> qualification, it's one.
>>
>>> Is 0.0 one sig fig or two?
>> Two.
>>
>>> (Just vaguely curious. Also curious as to
>>> whether a zero sig figures value is ever useful.)
>> Yes. They're order of magnitude estimates. 1 x 10^6 has one
>> significant figure. 10^6 has zero.
>
> By convention, nobody ever talks about 1 x 9.97^6 .
Not sure what the relevance is, since nobody had mentioned any such thing.
If it was intended as a gag, I don't catch the reference.
--
Erik Max Francis && max@alcyone.com && http://www.alcyone.com/max/
San Jose, CA, USA && 37 18 N 121 57 W && AIM/Y!M/Skype erikmaxfrancis
Love is the selfishness of two persons.
-- Antoine de la Salle
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| From | Mel <mwilson@the-wire.com> |
|---|---|
| Date | 2011-06-28 16:47 -0400 |
| Message-ID | <iudelu$tql$1@speranza.aioe.org> |
| In reply to | #8543 |
Erik Max Francis wrote: > Mel wrote: >> Erik Max Francis wrote: >> >>> Chris Angelico wrote: >>>> On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano >>>> <steve+comp.lang.python@pearwood.info> wrote: >>>>> Zero sig figure: 0 >>> That's not really zero significant figures; without further >>> qualification, it's one. >>> >>>> Is 0.0 one sig fig or two? >>> Two. >>> >>>> (Just vaguely curious. Also curious as to >>>> whether a zero sig figures value is ever useful.) >>> Yes. They're order of magnitude estimates. 1 x 10^6 has one >>> significant figure. 10^6 has zero. >> >> By convention, nobody ever talks about 1 x 9.97^6 . > > Not sure what the relevance is, since nobody had mentioned any such thing. > > If it was intended as a gag, I don't catch the reference. I get giddy once in a while.. push things to limits. It doesn't really mean anything. The point was that it's only the 2 in a number like 2e6 that is taken to have error bars. The 6 is always an absolute number. As is the 10 in 2*10**6. The thought also crossed my mind of a kind of continued fraction in reverse -- 2e1.3e.7 . I managed to keep quiet about that one. Mel.
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| From | Erik Max Francis <max@alcyone.com> |
|---|---|
| Date | 2011-06-28 14:01 -0700 |
| Message-ID | <67ednYGA8ICp3JfTnZ2dnUVZ5tOdnZ2d@giganews.com> |
| In reply to | #8552 |
Mel wrote:
> Erik Max Francis wrote:
>> Mel wrote:
>>> By convention, nobody ever talks about 1 x 9.97^6 .
>> Not sure what the relevance is, since nobody had mentioned any such thing.
>>
>> If it was intended as a gag, I don't catch the reference.
>
> I get giddy once in a while.. push things to limits. It doesn't really mean
> anything. The point was that it's only the 2 in a number like 2e6 that is
> taken to have error bars. The 6 is always an absolute number. As is the 10
> in 2*10**6.
They're not absolute numbers. It's just that the whole convention
surrounding significant digits means that the figure is accurate to the
last significant digit, plus or minus the range that would round to it.
That would be true for any base, it's just that we use base 10.
If the error bars are something other than that, they're either written
down explicitly (they need not even be symmetric), or they're written
with the convention of using parentheses to indicate the (symmetric)
error in the final set of significant digits. For instance, RPP 2010*
has a figure for Newton's gravitational constant of 6.67428(67) x 10^-11
m^3/(kg s^2), which means (6.67428 +- 0.00067) x 10^-11 m^3/(kg s^2).
.
* http://pdg.lbl.gov/2011/reviews/rpp2011-rev-phys-constants.pdf
--
Erik Max Francis && max@alcyone.com && http://www.alcyone.com/max/
San Jose, CA, USA && 37 18 N 121 57 W && AIM/Y!M/Skype erikmaxfrancis
When in doubt, C4.
-- Jamie Hyneman
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| From | Steven D'Aprano <steve+comp.lang.python@pearwood.info> |
|---|---|
| Date | 2011-06-28 18:35 +1000 |
| Message-ID | <4e099259$0$29991$c3e8da3$5496439d@news.astraweb.com> |
| In reply to | #8519 |
On Tue, 28 Jun 2011 01:16 pm Chris Angelico wrote: > On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano > <steve+comp.lang.python@pearwood.info> wrote: >> Zero sig figure: 0 >> > > Is 0.0 one sig fig or two? (Just vaguely curious. Also curious as to > whether a zero sig figures value is ever useful.) Two. I was actually being slightly silly about zero fig figures. Although, I suppose, if you genuinely had zero significant figures, you couldn't tell what the number was at all, so you'd need to use a NaN :) -- Steven
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| From | Erik Max Francis <max@alcyone.com> |
|---|---|
| Date | 2011-06-28 11:59 -0700 |
| Message-ID | <K9KdnaJWycA0uZfTnZ2dnUVZ5qudnZ2d@giganews.com> |
| In reply to | #8530 |
Steven D'Aprano wrote:
> On Tue, 28 Jun 2011 01:16 pm Chris Angelico wrote:
>
>> On Tue, Jun 28, 2011 at 12:56 PM, Steven D'Aprano
>> <steve+comp.lang.python@pearwood.info> wrote:
>>> Zero sig figure: 0
>>>
>> Is 0.0 one sig fig or two? (Just vaguely curious. Also curious as to
>> whether a zero sig figures value is ever useful.)
>
> Two. I was actually being slightly silly about zero fig figures.
>
> Although, I suppose, if you genuinely had zero significant figures, you
> couldn't tell what the number was at all, so you'd need to use a NaN :)
No, values with zero significant figures are just order of magnitude
estimates. They're used fairly often when doing very vague estimates,
but obviously they're subject to pretty atrocious rounding error.
For instance, let's do an order of magnitude estimate for the Planck
energy. The most obvious method is to start with the Planck mass. In
SI, it's about 2 x 10^-8 kg, or on the order of 10^-8 kg (zero
significant figures). To convert to energy, multiply by c^2. c = 3 x
10^8 m/s, so c^2 = 9 x 10^16 m^2/s^2, or about 10^17 m^2/s^2, so the
Planck energy is on the order of 10^9 J. That's a calculation to zero
significant figures.
--
Erik Max Francis && max@alcyone.com && http://www.alcyone.com/max/
San Jose, CA, USA && 37 18 N 121 57 W && AIM/Y!M/Skype erikmaxfrancis
Love is the selfishness of two persons.
-- Antoine de la Salle
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| From | Erik Max Francis <max@alcyone.com> |
|---|---|
| Date | 2011-06-27 20:49 -0700 |
| Message-ID | <_5GdnZSH4tWr0pTTnZ2dnUVZ5rmdnZ2d@giganews.com> |
| In reply to | #8518 |
Steven D'Aprano wrote:
> On Tue, 28 Jun 2011 06:53 am Ethan Furman wrote:
>
>> Harold wrote:
> [...]
>>>>>> Empirical('1200.').significance
>>> 2
>
> Well, that's completely wrong. It should be 4.
>
>>>>>> Empirical('1200.0').significance
>>> 5
>> What about when 1200 is actually 4 significant digits? Or 3?
>
> Then you shouldn't write it as 1200.0. By definition, zeros on the right are
> significant. If you don't want zeroes on the right to count, you have to
> not show them.
>
> Five sig figures: 1200.0
> Four sig figures: 1200
> Three sig figures: 1.20e3
> Two sig figures: 1.2e3
> One sig figure: 1e3
> Zero sig figure: 0
That last one is not true; 0 is a one-significant figure estimate, and
represents a value between -0.5 and 0.5. (It's true that zeroes to the
left are never significant, but not when there's nothing in the figure
but zeroes.)
A zero-significant figure would be an order of magnitude estimate only.
These aren't usually done in the "e" scientific notation, but it would
be something like 10^3 (if we assume ^ is exponentiation, not the Python
operator).
c^2 is 9 x 10^16 m^2/s^2 to one significant figure. It's 10^17 m^2/s^2
to zero (order of magnitude estimate).
--
Erik Max Francis && max@alcyone.com && http://www.alcyone.com/max/
San Jose, CA, USA && 37 18 N 121 57 W && AIM/Y!M/Skype erikmaxfrancis
I would have liked to have seen Montana.
-- Cpt. Vasily Borodin
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