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| Started by | Wanderer <wanderer@dialup4less.com> |
|---|---|
| First post | 2012-09-10 12:39 -0700 |
| Last post | 2012-11-10 08:05 -0500 |
| Articles | 10 — 5 participants |
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Numpy combine channels Wanderer <wanderer@dialup4less.com> - 2012-09-10 12:39 -0700
Re: Numpy combine channels Wanderer <wanderer@dialup4less.com> - 2012-09-10 12:56 -0700
RE: Numpy combine channels Nick Cash <nick.cash@npcinternational.com> - 2012-09-10 19:50 +0000
Re: Numpy combine channels MRAB <python@mrabarnett.plus.com> - 2012-09-10 21:11 +0100
Re: Numpy combine channels Wanderer <wanderer@dialup4less.com> - 2012-09-10 13:14 -0700
Re: Numpy combine channels Wanderer <wanderer@dialup4less.com> - 2012-09-10 13:15 -0700
Re: Numpy combine channels Wanderer <wanderer@dialup4less.com> - 2012-09-10 13:15 -0700
Re: Numpy combine channels Wanderer <wanderer@dialup4less.com> - 2012-09-10 13:14 -0700
Re: Numpy combine channels aahz@pythoncraft.com (Aahz) - 2012-11-09 20:30 -0800
Re: Numpy combine channels Dave Angel <d@davea.name> - 2012-11-10 08:05 -0500
| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2012-09-10 12:39 -0700 |
| Subject | Numpy combine channels |
| Message-ID | <de5d9415-f3d8-47b9-bcc2-822dc57fd1d8@googlegroups.com> |
I have an array generated by audiolab of left and right stereo channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine the left and right channels to get an array [2,3,5]. Is there a numpy command to do that? Thanks
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| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2012-09-10 12:56 -0700 |
| Message-ID | <c8f58c78-b16b-4d86-ae1a-604d904fa757@googlegroups.com> |
| In reply to | #28845 |
On Monday, September 10, 2012 3:39:11 PM UTC-4, Wanderer wrote: > I have an array generated by audiolab of left and right stereo channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine the left and right channels to get an array [2,3,5]. Is there a numpy command to do that? > > > > Thanks I figured it out. numpy.sum(array, axis=1).
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| From | Nick Cash <nick.cash@npcinternational.com> |
|---|---|
| Date | 2012-09-10 19:50 +0000 |
| Message-ID | <mailman.464.1347307538.27098.python-list@python.org> |
| In reply to | #28845 |
> I have an array generated by audiolab of left and right stereo > channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine > the left and right channels to get an array [2,3,5]. Is there a numpy > command to do that? You may be over-thinking this, and numpy might not be necessary. A simple solution would be just a quick list comprehension: stereo_array = [[1, 1], [1, 2], [2, 3]] mono_array = [l+r for (l, r) in stereo_array] Thanks, Nick Cash
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| From | MRAB <python@mrabarnett.plus.com> |
|---|---|
| Date | 2012-09-10 21:11 +0100 |
| Message-ID | <mailman.465.1347307911.27098.python-list@python.org> |
| In reply to | #28845 |
On 10/09/2012 20:39, Wanderer wrote:
> I have an array generated by audiolab of left and right stereo
> channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine
> the left and right channels to get an array [2,3,5]. Is there a numpy
> command to do that?
>
>>> import numpy
>>> numpy.array([[1,1],[1,2],[2,3]], dtype="i")
array([[1, 1],
[1, 2],
[2, 3]])
>>> a[:, 0]
array([1, 1, 2])
>>> a[:, 1]
array([1, 2, 3])
>>> a[:, 0] + a[:, 1]
array([2, 3, 5])
But should they be added together to make mono?
Suppose, for example, that both channels have a maximum value. Their
sum would be _twice_ the maximum.
Therefore, I think that it should probably be the average.
>>> (a[:, 0] + a[:, 1]) / 2
array([1, 1, 2])
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| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2012-09-10 13:14 -0700 |
| Message-ID | <0d091492-39e0-42b3-a383-9853af33136f@googlegroups.com> |
| In reply to | #28848 |
On Monday, September 10, 2012 4:12:40 PM UTC-4, MRAB wrote: > On 10/09/2012 20:39, Wanderer wrote: > > > I have an array generated by audiolab of left and right stereo > > > channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine > > > the left and right channels to get an array [2,3,5]. Is there a numpy > > > command to do that? > > > > > >>> import numpy > > >>> numpy.array([[1,1],[1,2],[2,3]], dtype="i") > > array([[1, 1], > > [1, 2], > > [2, 3]]) > > >>> a[:, 0] > > array([1, 1, 2]) > > >>> a[:, 1] > > array([1, 2, 3]) > > >>> a[:, 0] + a[:, 1] > > array([2, 3, 5]) > > > > But should they be added together to make mono? > > > > Suppose, for example, that both channels have a maximum value. Their > > sum would be _twice_ the maximum. > > > > Therefore, I think that it should probably be the average. > > > > >>> (a[:, 0] + a[:, 1]) / 2 > > array([1, 1, 2]) I'm decoding morse code. So it's CV dots and dashes.
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| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2012-09-10 13:15 -0700 |
| Message-ID | <45a73671-552e-491e-a1ff-27d7a3fde52e@googlegroups.com> |
| In reply to | #28849 |
On Monday, September 10, 2012 4:14:18 PM UTC-4, Wanderer wrote:
> On Monday, September 10, 2012 4:12:40 PM UTC-4, MRAB wrote:
>
> > On 10/09/2012 20:39, Wanderer wrote:
>
> >
>
> > > I have an array generated by audiolab of left and right stereo
>
> >
>
> > > channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine
>
> >
>
> > > the left and right channels to get an array [2,3,5]. Is there a numpy
>
> >
>
> > > command to do that?
>
> >
>
> > >
>
> >
>
> > >>> import numpy
>
> >
>
> > >>> numpy.array([[1,1],[1,2],[2,3]], dtype="i")
>
> >
>
> > array([[1, 1],
>
> >
>
> > [1, 2],
>
> >
>
> > [2, 3]])
>
> >
>
> > >>> a[:, 0]
>
> >
>
> > array([1, 1, 2])
>
> >
>
> > >>> a[:, 1]
>
> >
>
> > array([1, 2, 3])
>
> >
>
> > >>> a[:, 0] + a[:, 1]
>
> >
>
> > array([2, 3, 5])
>
> >
>
> >
>
> >
>
> > But should they be added together to make mono?
>
> >
>
> >
>
> >
>
> > Suppose, for example, that both channels have a maximum value. Their
>
> >
>
> > sum would be _twice_ the maximum.
>
> >
>
> >
>
> >
>
> > Therefore, I think that it should probably be the average.
>
> >
>
> >
>
> >
>
> > >>> (a[:, 0] + a[:, 1]) / 2
>
> >
>
> > array([1, 1, 2])
>
>
>
> I'm decoding morse code. So it's CV dots and dashes.
In case anyone is interested, here is the full code.
# morsecode.py
import numpy as np
from scikits.audiolab import wavread
from scipy.signal import decimate
from pylab import plot
from pylab import show
import os
def movingaverage(interval, window_size):
window = np.ones(int(window_size)) / float(window_size)
return np.convolve(interval, window, 'same')
def wav2morse(resultDir, filename):
""" Convert a wave file to morse code
resultDir: directory for wave file and results
filename: wave file name
"""
data, _fs, _enc = wavread(resultDir + '\\' + filename)
data = np.sum(data, axis=1)
data = np.fabs(data)
data = movingaverage(data, 100)
data = decimate(data, 2)
highcount = 0
lowcount = 0
fileBase, _fileExt = os.path.splitext(filename)
f = open(resultDir + '\\' + fileBase + '.txt', 'w')
for d in data:
if d > 0.3:
if lowcount > 3000:
f.write(' ')
lowcount = 0
highcount += 1
else:
if highcount > 3000:
f.write('-')
elif highcount > 1000:
f.write('.')
highcount = 0
lowcount += 1
f.close()
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| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2012-09-10 13:15 -0700 |
| Message-ID | <mailman.467.1347308157.27098.python-list@python.org> |
| In reply to | #28849 |
On Monday, September 10, 2012 4:14:18 PM UTC-4, Wanderer wrote:
> On Monday, September 10, 2012 4:12:40 PM UTC-4, MRAB wrote:
>
> > On 10/09/2012 20:39, Wanderer wrote:
>
> >
>
> > > I have an array generated by audiolab of left and right stereo
>
> >
>
> > > channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine
>
> >
>
> > > the left and right channels to get an array [2,3,5]. Is there a numpy
>
> >
>
> > > command to do that?
>
> >
>
> > >
>
> >
>
> > >>> import numpy
>
> >
>
> > >>> numpy.array([[1,1],[1,2],[2,3]], dtype="i")
>
> >
>
> > array([[1, 1],
>
> >
>
> > [1, 2],
>
> >
>
> > [2, 3]])
>
> >
>
> > >>> a[:, 0]
>
> >
>
> > array([1, 1, 2])
>
> >
>
> > >>> a[:, 1]
>
> >
>
> > array([1, 2, 3])
>
> >
>
> > >>> a[:, 0] + a[:, 1]
>
> >
>
> > array([2, 3, 5])
>
> >
>
> >
>
> >
>
> > But should they be added together to make mono?
>
> >
>
> >
>
> >
>
> > Suppose, for example, that both channels have a maximum value. Their
>
> >
>
> > sum would be _twice_ the maximum.
>
> >
>
> >
>
> >
>
> > Therefore, I think that it should probably be the average.
>
> >
>
> >
>
> >
>
> > >>> (a[:, 0] + a[:, 1]) / 2
>
> >
>
> > array([1, 1, 2])
>
>
>
> I'm decoding morse code. So it's CV dots and dashes.
In case anyone is interested, here is the full code.
# morsecode.py
import numpy as np
from scikits.audiolab import wavread
from scipy.signal import decimate
from pylab import plot
from pylab import show
import os
def movingaverage(interval, window_size):
window = np.ones(int(window_size)) / float(window_size)
return np.convolve(interval, window, 'same')
def wav2morse(resultDir, filename):
""" Convert a wave file to morse code
resultDir: directory for wave file and results
filename: wave file name
"""
data, _fs, _enc = wavread(resultDir + '\\' + filename)
data = np.sum(data, axis=1)
data = np.fabs(data)
data = movingaverage(data, 100)
data = decimate(data, 2)
highcount = 0
lowcount = 0
fileBase, _fileExt = os.path.splitext(filename)
f = open(resultDir + '\\' + fileBase + '.txt', 'w')
for d in data:
if d > 0.3:
if lowcount > 3000:
f.write(' ')
lowcount = 0
highcount += 1
else:
if highcount > 3000:
f.write('-')
elif highcount > 1000:
f.write('.')
highcount = 0
lowcount += 1
f.close()
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| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2012-09-10 13:14 -0700 |
| Message-ID | <mailman.466.1347308061.27098.python-list@python.org> |
| In reply to | #28848 |
On Monday, September 10, 2012 4:12:40 PM UTC-4, MRAB wrote: > On 10/09/2012 20:39, Wanderer wrote: > > > I have an array generated by audiolab of left and right stereo > > > channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine > > > the left and right channels to get an array [2,3,5]. Is there a numpy > > > command to do that? > > > > > >>> import numpy > > >>> numpy.array([[1,1],[1,2],[2,3]], dtype="i") > > array([[1, 1], > > [1, 2], > > [2, 3]]) > > >>> a[:, 0] > > array([1, 1, 2]) > > >>> a[:, 1] > > array([1, 2, 3]) > > >>> a[:, 0] + a[:, 1] > > array([2, 3, 5]) > > > > But should they be added together to make mono? > > > > Suppose, for example, that both channels have a maximum value. Their > > sum would be _twice_ the maximum. > > > > Therefore, I think that it should probably be the average. > > > > >>> (a[:, 0] + a[:, 1]) / 2 > > array([1, 1, 2]) I'm decoding morse code. So it's CV dots and dashes.
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| From | aahz@pythoncraft.com (Aahz) |
|---|---|
| Date | 2012-11-09 20:30 -0800 |
| Message-ID | <k7kl8b$5g0$1@panix5.panix.com> |
| In reply to | #28848 |
In article <mailman.465.1347307911.27098.python-list@python.org>, MRAB <python-list@python.org> wrote: >On 10/09/2012 20:39, Wanderer wrote: >> >> I have an array generated by audiolab of left and right stereo >> channels. It looks like [[1,1],[1,2],[2,3]]. I would like to combine >> the left and right channels to get an array [2,3,5]. Is there a numpy >> command to do that? > >>>> import numpy >>>> numpy.array([[1,1],[1,2],[2,3]], dtype="i") >array([[1, 1], > [1, 2], > [2, 3]]) >>>> a[:, 0] >array([1, 1, 2]) >>>> a[:, 1] >array([1, 2, 3]) >>>> a[:, 0] + a[:, 1] >array([2, 3, 5]) > >But should they be added together to make mono? > >Suppose, for example, that both channels have a maximum value. Their >sum would be _twice_ the maximum. > >Therefore, I think that it should probably be the average. > > >>> (a[:, 0] + a[:, 1]) / 2 >array([1, 1, 2]) I'd actually think it should be the max. Consider a stereo where one side is playing a booming bass while the other side is playing a rest note -- should the mono combination be half as loud as as the bass? -- Aahz (aahz@pythoncraft.com) <*> http://www.pythoncraft.com/ "....Normal is what cuts off your sixth finger and your tail..." --Siobhan
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| From | Dave Angel <d@davea.name> |
|---|---|
| Date | 2012-11-10 08:05 -0500 |
| Message-ID | <mailman.3534.1352552737.27098.python-list@python.org> |
| In reply to | #33075 |
On 11/09/2012 11:30 PM, Aahz wrote: > In article <mailman.465.1347307911.27098.python-list@python.org>, > MRAB <python-list@python.org> wrote: >> <snip> >> >> But should they be added together to make mono? >> >> Suppose, for example, that both channels have a maximum value. Their >> sum would be _twice_ the maximum. >> >> Therefore, I think that it should probably be the average. >> >>>>> (a[:, 0] + a[:, 1]) / 2 >> array([1, 1, 2]) > I'd actually think it should be the max. Consider a stereo where one > side is playing a booming bass while the other side is playing a rest > note -- should the mono combination be half as loud as as the bass? max would sound awful. The right answer is to add them with weighting, then scale the whole waveform according to a new calculation of clipping. Just like a mixer, you have level controls on each input, then an overall gain. So if the inputs were x and y, the output would be gain *( x_scale * x + y_scale * y), but it'd normally be done in two passes, so as to minimize the places that are clipped, while maximizing the average. it's also possible to have gain vary across the time axis, like an agc. But you wouldn't want that as a default, as it'd destroy the dynamics of a musical piece. One more consideration. If these are unsigned values (eg. 0 to 255), then you should adjust both signals by 128 before storing them as signed values, do your arithmetic, and then adjust again by adding 128. You could do the algebraic equivalent, but the programming would be much simpler on signed values. -- DaveA
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