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Re: testing if a list contains a sublist

Started byPeter Otten <__peter__@web.de>
First post2011-08-16 09:44 +0200
Last post2011-08-16 09:44 +0200
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  Re: testing if a list contains a sublist Peter Otten <__peter__@web.de> - 2011-08-16 09:44 +0200

#11522 — Re: testing if a list contains a sublist

FromPeter Otten <__peter__@web.de>
Date2011-08-16 09:44 +0200
SubjectRe: testing if a list contains a sublist
Message-ID<mailman.42.1313480614.27778.python-list@python.org>
Johannes wrote:

> what is the best way to check if a given list (lets call it l1) is
> totally contained in a second list (l2)?
> 
> for example:
> l1 = [1,2], l2 = [1,2,3,4,5] -> l1 is contained in l2
> l1 = [1,2,2,], l2 = [1,2,3,4,5] -> l1 is not contained in l2
> l1 = [1,2,3], l2 = [1,3,5,7] -> l1 is not contained in l2
> 
> my problem is the second example, which makes it impossible to work with
> sets insteads of lists. But something like set.issubset for lists would
> be nice.

Would [1, 2, 1] be contained in [1, 1, 2]? You have received an answer that 
assumes yes and another that assume no.

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