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Groups > comp.lang.python > #17536 > unrolled thread

Transform two tuples item by item

Started byGnarlodious <gnarlodious@gmail.com>
First post2011-12-19 18:04 -0800
Last post2011-12-19 19:40 -0800
Articles 4 — 3 participants

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  Transform two tuples item by item Gnarlodious <gnarlodious@gmail.com> - 2011-12-19 18:04 -0800
    Re: Transform two tuples item by item Tim Chase <python.list@tim.thechases.com> - 2011-12-19 20:42 -0600
    Re: Transform two tuples item by item Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-12-20 03:40 +0000
    Re: Transform two tuples item by item Gnarlodious <gnarlodious@gmail.com> - 2011-12-19 19:40 -0800

#17536 — Transform two tuples item by item

FromGnarlodious <gnarlodious@gmail.com>
Date2011-12-19 18:04 -0800
SubjectTransform two tuples item by item
Message-ID<21814930.66.1324346655123.JavaMail.geo-discussion-forums@prmw6>
What is the best way to operate on a tuple of values transforming them against a tuple of operations? Result can be a list or tuple:

tup=(35, '34', 0, 1, 31, 0, '&#26082;&#28639;')

from cgi import escape
[tup[0], "<span class='H'>{}</span>".format(tup[1]), bool(tup[2]), bool(tup[3]), tup[4], bool(tup[5]), escape(tup[6])]

-> [35, "<span class='H'>34</span>", False, True, 31, False, '&amp;#26082;&amp;#28639;']

But I want to loop rather than subscripting.

-- Gnarlie

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#17537

FromTim Chase <python.list@tim.thechases.com>
Date2011-12-19 20:42 -0600
Message-ID<mailman.3840.1324348945.27778.python-list@python.org>
In reply to#17536
On 12/19/11 20:04, Gnarlodious wrote:
> What is the best way to operate on a tuple of values
> transforming them against a tuple of operations? Result can be
> a list or tuple:
>
> tup=(35, '34', 0, 1, 31, 0, '&#26082;&#28639;')
>
> from cgi import escape
> [tup[0], "<span> class='H'>{}</span>".format(tup[1]), bool(tup[2]),
> bool(tup[3]), tup[4], bool(tup[5]), escape(tup[6])]
>
> ->  [35, "<span class='H'>34</span>", False, True, 31, False,
> '&amp;#26082;&amp;#28639;']
>
> But I want to loop rather than subscripting.

Well, you can do something like

 >>> from cgi import escape
 >>> nop = lambda x: x
 >>> tup = (35, '34', 0, 1, 31, 0, '&#26082;&#28639;')
 >>> ops = [nop, "<span class='H'>{0}</span>".format, bool, bool, 
nop, bool, escape]
 >>> [f(x) for f, x in zip(ops,tup)]
[35, "<span class='H'>34</span>", False, True, 31, False, 
'&amp;#26082;&amp;#28639;']

Note #1: I had to change your format from "{}" to "{0}", at least 
in 2.6 I've got here)

Note #2: it's spelled ".format" not ".format()" which puts the 
function reference in the "ops" list, not the results of calling it.

-tkc


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#17545

FromSteven D'Aprano <steve+comp.lang.python@pearwood.info>
Date2011-12-20 03:40 +0000
Message-ID<4ef00394$0$11091$c3e8da3@news.astraweb.com>
In reply to#17536
On Mon, 19 Dec 2011 18:04:15 -0800, Gnarlodious wrote:

> What is the best way to operate on a tuple of values transforming them
> against a tuple of operations? Result can be a list or tuple:

Create a list of functions:

ops = [lambda obj: obj,
       "<span class='H'>{}</span>".format,
       bool,
       bool,
       lambda obj: obj,
       bool,
       escape,
      ]

then use zip to pair them up with their arguments:

results = [f(x) for f,x in zip(ops, tup)]



-- 
Steven

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#17550

FromGnarlodious <gnarlodious@gmail.com>
Date2011-12-19 19:40 -0800
Message-ID<10253307.963.1324352410950.JavaMail.geo-discussion-forums@pruu23>
In reply to#17536
Wow, that is so elegant. Python is awesome.

-- Gnarlie

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