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Groups > comp.lang.python > #98907 > unrolled thread
| Started by | Seymore4Head <Seymore4Head@Hotmail.invalid> |
|---|---|
| First post | 2015-11-16 23:29 -0500 |
| Last post | 2015-11-17 10:31 +0100 |
| Articles | 6 — 3 participants |
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palindrome Seymore4Head <Seymore4Head@Hotmail.invalid> - 2015-11-16 23:29 -0500
Re: palindrome Abhiram R <abhi.darkness@gmail.com> - 2015-11-17 10:09 +0530
Re: palindrome Seymore4Head <Seymore4Head@Hotmail.invalid> - 2015-11-16 23:48 -0500
Re: palindrome Abhiram R <abhi.darkness@gmail.com> - 2015-11-17 10:25 +0530
Re: palindrome Peter Otten <__peter__@web.de> - 2015-11-17 10:48 +0100
Re: palindrome Peter Otten <__peter__@web.de> - 2015-11-17 10:31 +0100
| From | Seymore4Head <Seymore4Head@Hotmail.invalid> |
|---|---|
| Date | 2015-11-16 23:29 -0500 |
| Subject | palindrome |
| Message-ID | <s4bl4bd739gfq92c5hipb16grv8a5fh5pb@4ax.com> |
http://www.practicepython.org/exercise/2014/03/12/06-string-lists.html
Here is my answers. What would make it better?
import random
str1=""
letcount=4
count=0
abc='abcdefghijklmnopqrstuvwxyz'
while True:
for i in range(letcount):
a=random.choice(abc)
str1+=a
print str1
count+=1
if str1==str1[::-1]:
break
else:
str1=""
print "Tries= ",count
print str1
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| From | Abhiram R <abhi.darkness@gmail.com> |
|---|---|
| Date | 2015-11-17 10:09 +0530 |
| Message-ID | <mailman.376.1447735216.16136.python-list@python.org> |
| In reply to | #98907 |
On Tue, Nov 17, 2015 at 9:59 AM, Seymore4Head <Seymore4Head@hotmail.invalid>
wrote:
> http://www.practicepython.org/exercise/2014/03/12/06-string-lists.html
>
> Here is my answers. What would make it better?
>
> import random
> str1=""
> letcount=4
> count=0
> abc='abcdefghijklmnopqrstuvwxyz'
> while True:
> for i in range(letcount):
> a=random.choice(abc)
> str1+=a
> print str1
> count+=1
> if str1==str1[::-1]:
> break
> else:
> str1=""
> print "Tries= ",count
> print str1
> --
>
>
The question asks to get an input from the user and print if it's a
palindrome or not.
It should be just
strA=raw_input()
if strA==strA[::-1]:
print "Palindrome"
else:
print "Not"
Right? Am I missing something? Why are you generating random strings and
trying to check for palindromes?
Thanks
Abhiram R (IRC - abhiii5459_ ; Twitter - https://twitter.com/abhiii5459)
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| From | Seymore4Head <Seymore4Head@Hotmail.invalid> |
|---|---|
| Date | 2015-11-16 23:48 -0500 |
| Message-ID | <78cl4bljie79vqr80d1g084jm8ma3k0r9k@4ax.com> |
| In reply to | #98908 |
On Tue, 17 Nov 2015 10:09:27 +0530, Abhiram R <abhi.darkness@gmail.com> wrote: >On Tue, Nov 17, 2015 at 9:59 AM, Seymore4Head <Seymore4Head@hotmail.invalid> >wrote: > >> http://www.practicepython.org/exercise/2014/03/12/06-string-lists.html >> >> Here is my answers. What would make it better? >> >> import random >> str1="" >> letcount=4 >> count=0 >> abc='abcdefghijklmnopqrstuvwxyz' >> while True: >> for i in range(letcount): >> a=random.choice(abc) >> str1+=a >> print str1 >> count+=1 >> if str1==str1[::-1]: >> break >> else: >> str1="" >> print "Tries= ",count >> print str1 >> -- >> >> ? > >The question asks to get an input from the user and print if it's a >palindrome or not. >It should be just > >strA=raw_input() >if strA==strA[::-1]: > print "Palindrome" >else: > print "Not" > >Right? Am I missing something? Why are you generating random strings and >trying to check for palindromes?? > The instructions do ask for input. I am lazy. I thought it would be cool to have random input instead of just typing a phrase.
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| From | Abhiram R <abhi.darkness@gmail.com> |
|---|---|
| Date | 2015-11-17 10:25 +0530 |
| Message-ID | <mailman.377.1447736189.16136.python-list@python.org> |
| In reply to | #98909 |
On Tue, Nov 17, 2015 at 10:18 AM, Seymore4Head <Seymore4Head@hotmail.invalid > wrote: > On Tue, 17 Nov 2015 10:09:27 +0530, Abhiram R > <abhi.darkness@gmail.com> wrote: > > >On Tue, Nov 17, 2015 at 9:59 AM, Seymore4Head > <Seymore4Head@hotmail.invalid> > >wrote: > > > >> http://www.practicepython.org/exercise/2014/03/12/06-string-lists.html > >> > >> Here is my answers. What would make it better? > >> > >> import random > >> str1="" > >> letcount=4 > >> count=0 > >> abc='abcdefghijklmnopqrstuvwxyz' > >> while True: > >> for i in range(letcount): > >> a=random.choice(abc) > >> str1+=a > >> print str1 > >> count+=1 > >> if str1==str1[::-1]: > >> break > >> else: > >> str1="" > >> print "Tries= ",count > >> print str1 > >> -- > >> > >> ? > > > >The question asks to get an input from the user and print if it's a > >palindrome or not. > >It should be just > > > >strA=raw_input() > >if strA==strA[::-1]: > > print "Palindrome" > >else: > > print "Not" > > > >Right? Am I missing something? Why are you generating random strings and > >trying to check for palindromes?? > > > The instructions do ask for input. I am lazy. I thought it would be > cool to have random input instead of just typing a phrase. > -- > > Haha. Nice. Although with your length of string and the range you're picking from,the chances of you getting a palindrome are (1/24!) :D -- -Abhiram R
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| From | Peter Otten <__peter__@web.de> |
|---|---|
| Date | 2015-11-17 10:48 +0100 |
| Message-ID | <mailman.380.1447753729.16136.python-list@python.org> |
| In reply to | #98909 |
Abhiram R wrote: > Haha. Nice. Although with your length of string and the range you're > picking from,the chances of you getting a palindrome are (1/24!) :D Are you sure? >>> candidates = list(itertools.product(string.ascii_lowercase, repeat=4)) >>> len(candidates)/len([c for c in candidates if c == c[::-1]]) 676.0 That looks like one in 26**(length//2)
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| From | Peter Otten <__peter__@web.de> |
|---|---|
| Date | 2015-11-17 10:31 +0100 |
| Message-ID | <mailman.379.1447752716.16136.python-list@python.org> |
| In reply to | #98907 |
Seymore4Head wrote:
> http://www.practicepython.org/exercise/2014/03/12/06-string-lists.html
>
> Here is my answers. What would make it better?
1. Break the code into functions: one to generate a random string (the
desired length could be a parameter) and one to check if the string is a
palindrome. With that the loop will become
tries = 0
while True:
tries += 1
candidate = random_string(length=4)
print(candidate)
if is_palindrome(candidate):
break
print(tries, "tries")
2. If you plan to reuse these functions put the above code in a function
(let's call it main), too, that you invoke with
if __name__ == "__main__":
main()
to avoid that the code is executed when you import the module instead of
running it as a script.
3. For better readability add spaces around operators. There is a tool
called pep8 that will point out where you are breaking the standard Python
coding conventions.
4. Minor rewrites:
4.1 Can you rewrite the while loop as a for loop?
for tries in ...:
...
Hint 1: you can put a while loop into a generator
Hint 2: there's a ready-made solution in itertools.
4.2 Can you build the random string using a generator expression and
"".join(...)?
> import random
> str1=""
> letcount=4
> count=0
> abc='abcdefghijklmnopqrstuvwxyz'
> while True:
> for i in range(letcount):
> a=random.choice(abc)
> str1+=a
> print str1
> count+=1
> if str1==str1[::-1]:
> break
> else:
> str1=""
> print "Tries= ",count
> print str1
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