Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.python > #102548 > unrolled thread

Exception handling for socket.error in Python 3.5/RStudio

Started byshaunak.bangale@gmail.com
First post2016-02-05 11:58 -0800
Last post2016-02-19 10:07 -0800
Articles 2 on this page of 22 — 7 participants

Back to article view | Back to comp.lang.python

Contents

  Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 11:58 -0800
    Re: Exception handling for socket.error in Python 3.5/RStudio Nathan Hilterbrand <nhilterbrand@gmail.com> - 2016-02-05 15:07 -0500
      Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 12:11 -0800
        Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 12:17 -0800
    Re: Exception handling for socket.error in Python 3.5/RStudio "Martin A. Brown" <martin@linux-ip.net> - 2016-02-05 12:08 -0800
      Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 12:22 -0800
    Re: Exception handling for socket.error in Python 3.5/RStudio "Martin A. Brown" <martin@linux-ip.net> - 2016-02-05 12:44 -0800
    Re: Exception handling for socket.error in Python 3.5/RStudio "Martin A. Brown" <martin@linux-ip.net> - 2016-02-05 13:01 -0800
    Re: Exception handling for socket.error in Python 3.5/RStudio Chris Angelico <rosuav@gmail.com> - 2016-02-06 08:01 +1100
    Re: Exception handling for socket.error in Python 3.5/RStudio Bernardo Sulzbach <mafagafogigante@gmail.com> - 2016-02-05 19:08 -0200
      Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 13:26 -0800
        Re: Exception handling for socket.error in Python 3.5/RStudio Bernardo Sulzbach <mafagafogigante@gmail.com> - 2016-02-05 19:37 -0200
    Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 13:57 -0800
    Re: Exception handling for socket.error in Python 3.5/RStudio Chris Angelico <rosuav@gmail.com> - 2016-02-06 08:57 +1100
    Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-05 14:35 -0800
      Re: Exception handling for socket.error in Python 3.5/RStudio Chris Angelico <rosuav@gmail.com> - 2016-02-06 13:04 +1100
    Re: Exception handling for socket.error in Python 3.5/RStudio Shaunak Bangale <shaunak.bangale@gmail.com> - 2016-02-05 13:50 -0700
    Re: Exception handling for socket.error in Python 3.5/RStudio Shaunak Bangale <shaunak.bangale@gmail.com> - 2016-02-05 14:00 -0700
    Re: Exception handling for socket.error in Python 3.5/RStudio Shaunak Bangale <shaunak.bangale@gmail.com> - 2016-02-05 14:15 -0700
    Re: Exception handling for socket.error in Python 3.5/RStudio dieter <dieter@handshake.de> - 2016-02-07 09:23 +0100
      Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-08 00:04 -0800
        Re: Exception handling for socket.error in Python 3.5/RStudio shaunak.bangale@gmail.com - 2016-02-19 10:07 -0800

Page 2 of 2 — ← Prev page 1 [2]

#102647

Fromshaunak.bangale@gmail.com
Date2016-02-08 00:04 -0800
Message-ID<0e2fc62a-a4b8-4962-8737-b9cfdbafefc4@googlegroups.com>
In reply to#102618
On Sunday, February 7, 2016 at 1:23:32 AM UTC-7, dieter wrote:
> Shaunak Bangale <shaunak.bangale@gmail.com> writes:
> > ...
> > while (count > 0):
> >     try :
> >         # read line from file:
> >         print(file.readline())
> >         # parse
> >         parse_json(file.readline())
> >         count = count - 1
> >     except socket.error as e:
> >         print('Connection fail', e)
> >         print(traceback.format_exc())
> > ...
> > Error:
> > except socket.error as e:
> >                          ^
> > SyntaxError: invalid syntax
> 
> Are you sure, that there is no invisible character at the end
> of that line?
> 
> When I try code like the above (in PYthon 2.7), there is no
> "SyntaxError":
> 
> >>> while(False):
> ...     try :
> ...         # read line from file:
> ...         print(file.readline())
> ...         # parse
> ...         parse_json(file.readline())
> ...         count = count - 1
> ...     except socket.error as e:
> ...         print('Connection fail', e)
> ...         print(traceback.format_exc())
> ... 
> >>> 
> 
> 
> Another reason for your problem could be an older Python version.
> The "as" construct as part of the "except" clause is a more recent
> addition to Python.

Hi Dieter,

I typed that line again but didn't help. I am using Python 3.5.

[toc] | [prev] | [next] | [standalone]

#103210

Fromshaunak.bangale@gmail.com
Date2016-02-19 10:07 -0800
Message-ID<ae365fe9-0b6c-4cbe-96c4-59a6bcae7f10@googlegroups.com>
In reply to#102647
On Monday, February 8, 2016 at 1:05:08 AM UTC-7, shaunak...@gmail.com wrote:
> On Sunday, February 7, 2016 at 1:23:32 AM UTC-7, dieter wrote:
> > Shaunak Bangale <shaunak.bangale@gmail.com> writes:
> > > ...
> > > while (count > 0):
> > >     try :
> > >         # read line from file:
> > >         print(file.readline())
> > >         # parse
> > >         parse_json(file.readline())
> > >         count = count - 1
> > >     except socket.error as e:
> > >         print('Connection fail', e)
> > >         print(traceback.format_exc())
> > > ...
> > > Error:
> > > except socket.error as e:
> > >                          ^
> > > SyntaxError: invalid syntax
> > 
> > Are you sure, that there is no invisible character at the end
> > of that line?
> > 
> > When I try code like the above (in PYthon 2.7), there is no
> > "SyntaxError":
> > 
> > >>> while(False):
> > ...     try :
> > ...         # read line from file:
> > ...         print(file.readline())
> > ...         # parse
> > ...         parse_json(file.readline())
> > ...         count = count - 1
> > ...     except socket.error as e:
> > ...         print('Connection fail', e)
> > ...         print(traceback.format_exc())
> > ... 
> > >>> 
> > 
> > 
> > Another reason for your problem could be an older Python version.
> > The "as" construct as part of the "except" clause is a more recent
> > addition to Python.
> 
> Hi Dieter,
> 
> I typed that line again but didn't help. I am using Python 3.5.
-------------

Hi people, it finally worked. One problem was with the way modules were set up, so installed anacoda and using accessing it through PyCharm. It's working well now. Another problem was with the initiation command, had to renew the password and that's working too. I sincerely thank everyone here who tried to help me. :) 
Have a great weekend guys!

-Shaun

[toc] | [prev] | [standalone]

Page 2 of 2 — ← Prev page 1 [2]

Back to top | Article view | comp.lang.python

csiph-web