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| Started by | Stefan Behnel <stefan_ml@behnel.de> |
|---|---|
| First post | 2011-04-05 10:16 +0200 |
| Last post | 2011-04-05 10:16 +0200 |
| Articles | 1 — 1 participant |
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Re: XML header with lxml Stefan Behnel <stefan_ml@behnel.de> - 2011-04-05 10:16 +0200
| From | Stefan Behnel <stefan_ml@behnel.de> |
|---|---|
| Date | 2011-04-05 10:16 +0200 |
| Subject | Re: XML header with lxml |
| Message-ID | <mailman.36.1301991392.9059.python-list@python.org> |
Jabba Laci, 04.04.2011 18:54:
> I want to construct an XML file with lxml but I don't find how to add
> the '<?xml version="1.0"?>' header.
This is not required. According to the XML spec, the default is:
<?xml version="1.0" encoding="utf-8" standalone="false"?>
So, unless you diverge from these values, you do not need an XML
declaration in your file. If you want to output the declaration anyway, you
can simply prepend it to the string or write it into the output file before
serialising.
> from lxml import etree as ET
>
> html = ET.Element("html")
> print ET.tostring(html)
>
> simply prints
> <html/>
I imagine you are aware that HTML isn't XML.
Stefan
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