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Groups > comp.lang.python > #41603 > unrolled thread
| Started by | Ana Dionísio <anadionisio257@gmail.com> |
|---|---|
| First post | 2013-03-20 08:27 -0700 |
| Last post | 2013-03-20 20:47 +0000 |
| Articles | 7 — 6 participants |
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Lists and Decimal numbers Ana Dionísio <anadionisio257@gmail.com> - 2013-03-20 08:27 -0700
Re: Lists and Decimal numbers Wanderer <wanderer@dialup4less.com> - 2013-03-20 08:48 -0700
Re: Lists and Decimal numbers Peter Otten <__peter__@web.de> - 2013-03-20 16:52 +0100
Re: Lists and Decimal numbers Alister <alister.ware@ntlworld.com> - 2013-03-20 19:20 +0000
Re: Lists and Decimal numbers Mark Lawrence <breamoreboy@yahoo.co.uk> - 2013-03-20 19:53 +0000
Re: Lists and Decimal numbers Grant Edwards <invalid@invalid.invalid> - 2013-03-20 20:00 +0000
Re: Lists and Decimal numbers Alister <alister.ware@ntlworld.com> - 2013-03-20 20:47 +0000
| From | Ana Dionísio <anadionisio257@gmail.com> |
|---|---|
| Date | 2013-03-20 08:27 -0700 |
| Subject | Lists and Decimal numbers |
| Message-ID | <9d8e4386-e6f5-4303-8a6a-be2a16e45ce7@googlegroups.com> |
So, I have this script that puts in a list every minute in 24 hours
hour=[]
i=0
t=-(1.0/60.0)
while i<24*60:
i = i+1
t = t+(1.0/60.0)
hour.append([t])
When it is doing the cicle it can have all the decimal numbers, but I need to print the result with only 4 decimal numbers
How can I define the number of decimal numbers I want to print in this case? For example with 4 decimal numbers, it would print:
0.0000
0.0167
0.0333
...
Can you help?
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| From | Wanderer <wanderer@dialup4less.com> |
|---|---|
| Date | 2013-03-20 08:48 -0700 |
| Message-ID | <0180bf86-4d01-4840-9284-42cf4976b685@googlegroups.com> |
| In reply to | #41603 |
On Wednesday, March 20, 2013 11:27:30 AM UTC-4, Ana Dionísio wrote:
> So, I have this script that puts in a list every minute in 24 hours
>
>
>
> hour=[]
>
> i=0
>
> t=-(1.0/60.0)
>
> while i<24*60:
>
> i = i+1
>
> t = t+(1.0/60.0)
>
> hour.append([t])
>
>
>
> When it is doing the cicle it can have all the decimal numbers, but I need to print the result with only 4 decimal numbers
>
>
>
> How can I define the number of decimal numbers I want to print in this case? For example with 4 decimal numbers, it would print:
>
>
>
> 0.0000
>
> 0.0167
>
> 0.0333
>
> ...
>
>
>
> Can you help?
You can use round.
for t in hour:
print round(t,4)
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| From | Peter Otten <__peter__@web.de> |
|---|---|
| Date | 2013-03-20 16:52 +0100 |
| Message-ID | <mailman.3567.1363794723.2939.python-list@python.org> |
| In reply to | #41603 |
Ana Dionísio wrote:
> So, I have this script that puts in a list every minute in 24 hours
>
> hour=[]
> i=0
> t=-(1.0/60.0)
> while i<24*60:
> i = i+1
> t = t+(1.0/60.0)
> hour.append([t])
In many cases you can write
for i in range(...):
...
instead of incrementing manually.
> When it is doing the cicle it can have all the decimal numbers, but I need
> to print the result with only 4 decimal numbers
>
> How can I define the number of decimal numbers I want to print in this
> case? For example with 4 decimal numbers, it would print:
>
> 0.0000
> 0.0167
> 0.0333
> ...
>
> Can you help?
>>> for i in range(24*60):
... print "{:.4f}".format(i/60.0)
...
0.0000
0.0167
0.0333
0.0500
[...]
23.9500
23.9667
23.9833
>>>
See also
<http://docs.python.org/2/library/string.html#format-specification-mini-language>
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| From | Alister <alister.ware@ntlworld.com> |
|---|---|
| Date | 2013-03-20 19:20 +0000 |
| Message-ID | <t_n2t.145340$927.82085@fx23.fr7> |
| In reply to | #41605 |
On Wed, 20 Mar 2013 16:52:00 +0100, Peter Otten wrote:
> Ana Dionísio wrote:
>
>> So, I have this script that puts in a list every minute in 24 hours
>>
>> hour=[]
>> i=0 t=-(1.0/60.0)
>> while i<24*60:
>> i = i+1 t = t+(1.0/60.0)
>> hour.append([t])
>
> In many cases you can write
>
> for i in range(...):
> ...
>
> instead of incrementing manually.
>
>> When it is doing the cicle it can have all the decimal numbers, but I
>> need to print the result with only 4 decimal numbers
>>
>> How can I define the number of decimal numbers I want to print in this
>> case? For example with 4 decimal numbers, it would print:
>>
>> 0.0000 0.0167 0.0333 ...
>>
>> Can you help?
>
>
>>>> for i in range(24*60):
> ... print "{:.4f}".format(i/60.0)
> ...
> 0.0000 0.0167 0.0333 0.0500 [...]
> 23.9500 23.9667 23.9833
>>>>
>>>>
> See also
>
> <http://docs.python.org/2/library/string.html#format-specification-mini-
language>
and a list comprehension would streamline things further
t=[round(x*1.0/60),4 for x in range(1440)] #compatible with V2.7 & V3.0)
--
How many Zen Buddhist does it take to change a light bulb?
Two. One to change it and one not to change it.
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| From | Mark Lawrence <breamoreboy@yahoo.co.uk> |
|---|---|
| Date | 2013-03-20 19:53 +0000 |
| Message-ID | <mailman.3575.1363809193.2939.python-list@python.org> |
| In reply to | #41617 |
On 20/03/2013 19:20, Alister wrote:
> On Wed, 20 Mar 2013 16:52:00 +0100, Peter Otten wrote:
>
>> Ana Dionísio wrote:
>>
>>> So, I have this script that puts in a list every minute in 24 hours
>>>
>>> hour=[]
>>> i=0 t=-(1.0/60.0)
>>> while i<24*60:
>>> i = i+1 t = t+(1.0/60.0)
>>> hour.append([t])
>>
>> In many cases you can write
>>
>> for i in range(...):
>> ...
>>
>> instead of incrementing manually.
>>
>>> When it is doing the cicle it can have all the decimal numbers, but I
>>> need to print the result with only 4 decimal numbers
>>>
>>> How can I define the number of decimal numbers I want to print in this
>>> case? For example with 4 decimal numbers, it would print:
>>>
>>> 0.0000 0.0167 0.0333 ...
>>>
>>> Can you help?
>>
>>
>>>>> for i in range(24*60):
>> ... print "{:.4f}".format(i/60.0)
>> ...
>> 0.0000 0.0167 0.0333 0.0500 [...]
>> 23.9500 23.9667 23.9833
>>>>>
>>>>>
>> See also
>>
>> <http://docs.python.org/2/library/string.html#format-specification-mini-
> language>
>
>
> and a list comprehension would streamline things further
>
> t=[round(x*1.0/60),4 for x in range(1440)] #compatible with V2.7 & V3.0)
>
Really?
c:\Users\Mark\Python>python
Python 3.3.0 (v3.3.0:bd8afb90ebf2, Sep 29 2012, 10:55:48) [MSC v.1600 32
bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> t=[round(x*1.0/60),4 for x in range(1440)] #compatible with V2.7 &
V3.0)
File "<stdin>", line 1
t=[round(x*1.0/60),4 for x in range(1440)] #compatible with V2.7 &
V3.0)
^
SyntaxError: invalid syntax
--
Cheers.
Mark Lawrence
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| From | Grant Edwards <invalid@invalid.invalid> |
|---|---|
| Date | 2013-03-20 20:00 +0000 |
| Message-ID | <kid4h6$1hv$1@reader2.panix.com> |
| In reply to | #41617 |
On 2013-03-20, Alister <alister.ware@ntlworld.com> wrote:
> and a list comprehension would streamline things further
>
> t=[round(x*1.0/60),4 for x in range(1440)] #compatible with V2.7 & V3.0)
There's a typo in the above. It should be:
t = [round((x*1.0/60),4) for x in range(1440)]
--
Grant Edwards grant.b.edwards Yow! On the road, ZIPPY
at is a pinhead without a
gmail.com purpose, but never without
a POINT.
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| From | Alister <alister.ware@ntlworld.com> |
|---|---|
| Date | 2013-03-20 20:47 +0000 |
| Message-ID | <Afp2t.202953$VO5.3067@fx20.fr7> |
| In reply to | #41620 |
On Wed, 20 Mar 2013 20:00:38 +0000, Grant Edwards wrote: > On 2013-03-20, Alister <alister.ware@ntlworld.com> wrote: > >> and a list comprehension would streamline things further >> >> t=[round(x*1.0/60),4 for x in range(1440)] #compatible with V2.7 & >> V3.0) > > There's a typo in the above. It should be: > > t = [round((x*1.0/60),4) for x in range(1440)] Indeed a typo Many thanks for correcting -- "MacDonald has the gift on compressing the largest amount of words into the smallest amount of thoughts." -- Winston Churchill
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