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| Started by | liuerfire Wang <liuerfire@gmail.com> |
|---|---|
| First post | 2013-08-07 16:50 +0800 |
| Last post | 2013-08-21 13:01 -0700 |
| Articles | 3 — 3 participants |
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make elements of a list twice or more. liuerfire Wang <liuerfire@gmail.com> - 2013-08-07 16:50 +0800
Re: make elements of a list twice or more. alex23 <wuwei23@gmail.com> - 2013-08-20 13:42 +1000
Re: make elements of a list twice or more. Tobiah <toby@tobiah.org> - 2013-08-21 13:01 -0700
| From | liuerfire Wang <liuerfire@gmail.com> |
|---|---|
| Date | 2013-08-07 16:50 +0800 |
| Subject | make elements of a list twice or more. |
| Message-ID | <mailman.318.1375893821.1251.python-list@python.org> |
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Sorry for the title which didn't make clear.
Here is a list x = [b, a, c] (a, b, c are elements of x. Each of them are
different type). Now I wanna generate a new list as [b, b, a, a, c, c].
I know we can do like that:
tmp = []
for i in x:
tmp.append(i)
tmp.append(i)
However, I wander is there a more beautiful way to do it, like [i for i in
x]?
Thanks.
--
Best regards.
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| From | alex23 <wuwei23@gmail.com> |
|---|---|
| Date | 2013-08-20 13:42 +1000 |
| Message-ID | <kuuoj5$fj$1@dont-email.me> |
| In reply to | #52140 |
On 7/08/2013 6:50 PM, liuerfire Wang wrote: > Here is a list x = [b, a, c] (a, b, c are elements of x. Each of them > are different type). Now I wanna generate a new list as [b, b, a, a, c, c]. from itertools import chain new_list = list(chain.from_iterable(zip(x,x)))
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| From | Tobiah <toby@tobiah.org> |
|---|---|
| Date | 2013-08-21 13:01 -0700 |
| Message-ID | <52151C90.9080602@tobiah.org> |
| In reply to | #52140 |
On 08/07/2013 01:50 AM, liuerfire Wang wrote: > Sorry for the title which didn't make clear. > > Here is a list x = [b, a, c] (a, b, c are elements of x. Each of them are different type). Now I wanna generate a new list as [b, > b, a, a, c, c]. If you don't care about the order, you can do: x = x + x
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