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Groups > comp.lang.python > #26877 > unrolled thread
| Started by | Tamer Higazi <th982a@googlemail.com> |
|---|---|
| First post | 2012-08-10 17:31 +0200 |
| Last post | 2012-08-10 10:04 -0700 |
| Articles | 3 — 2 participants |
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Re: dictionary into desired variable.... Tamer Higazi <th982a@googlemail.com> - 2012-08-10 17:31 +0200
Re: dictionary into desired variable.... woooee@gmail.com - 2012-08-10 10:04 -0700
Re: dictionary into desired variable.... woooee@gmail.com - 2012-08-10 10:04 -0700
| From | Tamer Higazi <th982a@googlemail.com> |
|---|---|
| Date | 2012-08-10 17:31 +0200 |
| Subject | Re: dictionary into desired variable.... |
| Message-ID | <mailman.3166.1344612712.4697.python-list@python.org> |
Sorry, I ment of course list.... what I exaclty ment is that if I assign value = Number that I automaticly assign y[1][3][6][1][1] a new number. more detailled explained: let us say a would be x = [2,5,4] y = a[3] if I change y to [] I want the result to be x = [2,5,[]] and that's automaticly independently how deep i dig. Sorry for the inconvenience. Tamer Am 10.08.2012 16:31, schrieb Chris Angelico: > On Sat, Aug 11, 2012 at 12:02 AM, Tamer Higazi <th982a@googlemail.com> wrote: >> Hi! >> suppose you have a dictionary that looks like this: >> >> x = [1,3,6,1,1] which should represent a certain other variable. >> >> in reality it would represent: >> >> y[1][3][6][1][1] >> >> Now, how do I write a python routine, that points in this dictionary, >> where I should receive or set other values. > > For a start, that looks like a list, not a dictionary. A dict in > Python is a mapping, eg a hashtable - an unordered pairing of keys and > values. But this might do what you want: > > value = y > for idx in x: > value = value[idx] > > At the end of that, 'value' will be the same as 'y[1][3][6][1][1]'. > > If that's not what you mean, you may want to clarify your question some. > > Hope that helps! > > Chris Angelico
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| From | woooee@gmail.com |
|---|---|
| Date | 2012-08-10 10:04 -0700 |
| Message-ID | <mailman.3169.1344618284.4697.python-list@python.org> |
| In reply to | #26877 |
On Friday, August 10, 2012 8:31:48 AM UTC-7, Tamer Higazi wrote: > let us say a would be x = [2,5,4] > > y = a[3] > > if I change y to [] > > I want the result to be x = [2,5,[]] and that's automaticly There is no such thing as a[3] if a=[2,4,5]. And this is a list not a dictionary, so I would suggest a tutorial from the Python wiki page. You have to use a mutable container. Integers are not mutable. Lists, for example are. y=[4] x = [2,5,y] print x y[0]=10 print x
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| From | woooee@gmail.com |
|---|---|
| Date | 2012-08-10 10:04 -0700 |
| Message-ID | <d6c5ac27-be53-4074-bf54-80e8c303d183@googlegroups.com> |
| In reply to | #26877 |
On Friday, August 10, 2012 8:31:48 AM UTC-7, Tamer Higazi wrote: > let us say a would be x = [2,5,4] > > y = a[3] > > if I change y to [] > > I want the result to be x = [2,5,[]] and that's automaticly There is no such thing as a[3] if a=[2,4,5]. And this is a list not a dictionary, so I would suggest a tutorial from the Python wiki page. You have to use a mutable container. Integers are not mutable. Lists, for example are. y=[4] x = [2,5,y] print x y[0]=10 print x
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