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Groups > comp.lang.python > #97289 > unrolled thread
| Started by | Dave Farrance <df@see.replyto.invalid> |
|---|---|
| First post | 2015-10-01 17:36 +0100 |
| Last post | 2015-10-01 22:01 +0200 |
| Articles | 8 — 2 participants |
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matplotlib timer Dave Farrance <df@see.replyto.invalid> - 2015-10-01 17:36 +0100
Re: matplotlib timer Laura Creighton <lac@openend.se> - 2015-10-01 19:28 +0200
Re: matplotlib timer Dave Farrance <df@see.replyto.invalid> - 2015-10-01 18:45 +0100
Re: matplotlib timer Laura Creighton <lac@openend.se> - 2015-10-01 20:09 +0200
Re: matplotlib timer Dave Farrance <df@see.replyto.invalid> - 2015-10-01 20:03 +0100
Re: matplotlib timer Laura Creighton <lac@openend.se> - 2015-10-01 21:19 +0200
Re: matplotlib timer Dave Farrance <df@see.replyto.invalid> - 2015-10-01 20:47 +0100
Re: matplotlib timer Laura Creighton <lac@openend.se> - 2015-10-01 22:01 +0200
| From | Dave Farrance <df@see.replyto.invalid> |
|---|---|
| Date | 2015-10-01 17:36 +0100 |
| Subject | matplotlib timer |
| Message-ID | <3unq0b1qkisbudlj03q4qlu5t5ugpmo0th@4ax.com> |
I'm trying to set up the basics of a timer-scheduled function in
matplotlib and I can't figure out how to stop the timer. Maybe the
stop() method is dysfunctional in Ubuntu 14.04 or maybe I'm getting the
syntax wrong.
If anybody's got matplotlib installed, can you try this code and tell me
if it stops after one tick as it should -- or does it continue printing
every second without stopping as mine does?
#!/usr/bin/env python
import matplotlib.pyplot as P
def fn():
timer.stop()
print("tick")
fig, ax = P.subplots()
timer = fig.canvas.new_timer(interval=1000)
timer.add_callback(fn)
timer.start()
P.show()
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| From | Laura Creighton <lac@openend.se> |
|---|---|
| Date | 2015-10-01 19:28 +0200 |
| Message-ID | <mailman.304.1443720523.28679.python-list@python.org> |
| In reply to | #97289 |
In a message of Thu, 01 Oct 2015 17:36:50 +0100, Dave Farrance writes:
>I'm trying to set up the basics of a timer-scheduled function in
>matplotlib and I can't figure out how to stop the timer. Maybe the
>stop() method is dysfunctional in Ubuntu 14.04 or maybe I'm getting the
>syntax wrong.
>
>If anybody's got matplotlib installed, can you try this code and tell me
>if it stops after one tick as it should -- or does it continue printing
>every second without stopping as mine does?
>
>#!/usr/bin/env python
>import matplotlib.pyplot as P
>def fn():
> timer.stop()
> print("tick")
>fig, ax = P.subplots()
>timer = fig.canvas.new_timer(interval=1000)
>timer.add_callback(fn)
>timer.start()
>P.show()
>
debian unstable
Python 3.4.3+ (default, Jul 28 2015, 13:17:50)
mine ticks forever, too.
Laura
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| From | Dave Farrance <df@see.replyto.invalid> |
|---|---|
| Date | 2015-10-01 18:45 +0100 |
| Message-ID | <kqrq0bh67c3bt3shq24g9i72hlo3krr1e8@4ax.com> |
| In reply to | #97292 |
Laura Creighton <lac@openend.se> wrote:
>In a message of Thu, 01 Oct 2015 17:36:50 +0100, Dave Farrance writes:
>>I'm trying to set up the basics of a timer-scheduled function in
>>matplotlib and I can't figure out how to stop the timer. Maybe the
>>stop() method is dysfunctional in Ubuntu 14.04 or maybe I'm getting the
>>syntax wrong.
>>
>>If anybody's got matplotlib installed, can you try this code and tell me
>>if it stops after one tick as it should -- or does it continue printing
>>every second without stopping as mine does?
>>
>>#!/usr/bin/env python
>>import matplotlib.pyplot as P
>>def fn():
>> timer.stop()
>> print("tick")
>>fig, ax = P.subplots()
>>timer = fig.canvas.new_timer(interval=1000)
>>timer.add_callback(fn)
>>timer.start()
>>P.show()
>>
>
>debian unstable
>Python 3.4.3+ (default, Jul 28 2015, 13:17:50)
>
>mine ticks forever, too.
Thanks. I've just figured out how to stop the timer.
replace "timer.stop()" with
timer.single_shot = True
Yet the documentation says that it's mandatory for the GUI backend base
to implement stop() but that single_shot is optional. Ho hum.
http://matplotlib.org/api/backend_bases_api.html#matplotlib.backend_bases.TimerBase
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| From | Laura Creighton <lac@openend.se> |
|---|---|
| Date | 2015-10-01 20:09 +0200 |
| Message-ID | <mailman.306.1443722962.28679.python-list@python.org> |
| In reply to | #97294 |
In a message of Thu, 01 Oct 2015 18:45:06 +0100, Dave Farrance writes: >Yet the documentation says that it's mandatory for the GUI backend base >to implement stop() but that single_shot is optional. Ho hum. report as a bug. its a doc bug at least, but I think its a real bug, and your code should have worked. https://github.com/matplotlib/matplotlib/issues Laura
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| From | Dave Farrance <df@see.replyto.invalid> |
|---|---|
| Date | 2015-10-01 20:03 +0100 |
| Message-ID | <br0r0btskogeq3g9r0fh85dkqqpq3ov3s2@4ax.com> |
| In reply to | #97295 |
Laura Creighton <lac@openend.se> wrote: >In a message of Thu, 01 Oct 2015 18:45:06 +0100, Dave Farrance writes: >>Yet the documentation says that it's mandatory for the GUI backend base >>to implement stop() but that single_shot is optional. Ho hum. > >report as a bug. its a doc bug at least, but I think its a real bug, >and your code should have worked. > >https://github.com/matplotlib/matplotlib/issues OK, done. https://github.com/matplotlib/matplotlib/issues/5163
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| From | Laura Creighton <lac@openend.se> |
|---|---|
| Date | 2015-10-01 21:19 +0200 |
| Message-ID | <mailman.307.1443727170.28679.python-list@python.org> |
| In reply to | #97299 |
In a message of Thu, 01 Oct 2015 20:03:26 +0100, Dave Farrance writes: >Laura Creighton <lac@openend.se> wrote: > >>In a message of Thu, 01 Oct 2015 18:45:06 +0100, Dave Farrance writes: >>>Yet the documentation says that it's mandatory for the GUI backend base >>>to implement stop() but that single_shot is optional. Ho hum. >> >>report as a bug. its a doc bug at least, but I think its a real bug, >>and your code should have worked. >> >>https://github.com/matplotlib/matplotlib/issues > >OK, done. > Thank you. Can you add how you got it to work, and the doc you read that seems wrong? Laura
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| From | Dave Farrance <df@see.replyto.invalid> |
|---|---|
| Date | 2015-10-01 20:47 +0100 |
| Message-ID | <4d3r0bdalmomjk4jq4f62lbgr1hu3kgsfr@4ax.com> |
| In reply to | #97302 |
Laura Creighton <lac@openend.se> wrote: >In a message of Thu, 01 Oct 2015 20:03:26 +0100, Dave Farrance writes: >>Laura Creighton <lac@openend.se> wrote: >> >>>In a message of Thu, 01 Oct 2015 18:45:06 +0100, Dave Farrance writes: >>>>Yet the documentation says that it's mandatory for the GUI backend base >>>>to implement stop() but that single_shot is optional. Ho hum. >>> >>>report as a bug. its a doc bug at least, but I think its a real bug, >>>and your code should have worked. >>> >>>https://github.com/matplotlib/matplotlib/issues >> >>OK, done. >> > >Thank you. > >Can you add how you got it to work, and the doc you read >that seems wrong? OK.
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| From | Laura Creighton <lac@openend.se> |
|---|---|
| Date | 2015-10-01 22:01 +0200 |
| Message-ID | <mailman.308.1443729670.28679.python-list@python.org> |
| In reply to | #97304 |
In a message of Thu, 01 Oct 2015 20:47:10 +0100, Dave Farrance writes: >Laura Creighton <lac@openend.se> wrote: > >>In a message of Thu, 01 Oct 2015 20:03:26 +0100, Dave Farrance writes: >>>Laura Creighton <lac@openend.se> wrote: >>> >>>>In a message of Thu, 01 Oct 2015 18:45:06 +0100, Dave Farrance writes: >>>>>Yet the documentation says that it's mandatory for the GUI backend base >>>>>to implement stop() but that single_shot is optional. Ho hum. >>>> >>>>report as a bug. its a doc bug at least, but I think its a real bug, >>>>and your code should have worked. >>>> >>>>https://github.com/matplotlib/matplotlib/issues >>> >>>OK, done. >>> >> >>Thank you. >> >>Can you add how you got it to work, and the doc you read >>that seems wrong? > >OK. You, sir, are a champion. Thank you again. Laura
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