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Groups > comp.lang.python > #40726 > unrolled thread
| Started by | Sven <svenito@gmail.com> |
|---|---|
| First post | 2013-03-07 09:23 +0000 |
| Last post | 2013-03-07 08:37 -0500 |
| Articles | 2 — 2 participants |
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iterating over a list as if it were a circular list Sven <svenito@gmail.com> - 2013-03-07 09:23 +0000
Re: iterating over a list as if it were a circular list Roy Smith <roy@panix.com> - 2013-03-07 08:37 -0500
| From | Sven <svenito@gmail.com> |
|---|---|
| Date | 2013-03-07 09:23 +0000 |
| Subject | iterating over a list as if it were a circular list |
| Message-ID | <mailman.2993.1362648214.2939.python-list@python.org> |
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I was wondering what the best approach for the following might be. Say you have a list P of points and another list N of other items. You can always assume that len(N) <= len(P) Now I would like to iterate over P and place one N at each point. However if you run out of N I'd like to restart from N[0] and carry on until all the points have been populated. So far I've got for point in points: -- ./Sven
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| From | Roy Smith <roy@panix.com> |
|---|---|
| Date | 2013-03-07 08:37 -0500 |
| Message-ID | <roy-21CD9E.08370707032013@70-1-84-166.pools.spcsdns.net> |
| In reply to | #40726 |
In article <mailman.2993.1362648214.2939.python-list@python.org>, Sven <svenito@gmail.com> wrote: > I was wondering what the best approach for the following might be. > > Say you have a list P of points and another list N of other items. You can > always assume that > > len(N) <= len(P) > > Now I would like to iterate over P and place one N at each point. However > if you run out of N I'd like to restart from N[0] and carry on until all > the points have been populated. > So far I've got > > for point in points: I'm not completely following what you're trying to do, but I think what you're looking for is some combination of zip() and itertools.cycle(). pairs = zip(P, cycle(N))
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