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Groups > comp.lang.python > #11924 > unrolled thread
| Started by | Chris Angelico <rosuav@gmail.com> |
|---|---|
| First post | 2011-08-20 19:29 +0100 |
| Last post | 2011-08-21 15:16 -0700 |
| Articles | 6 — 4 participants |
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Re: extended slicing and negative stop value problem Chris Angelico <rosuav@gmail.com> - 2011-08-20 19:29 +0100
Re: extended slicing and negative stop value problem Max <maxmoroz@gmail.com> - 2011-08-20 11:52 -0700
Re: extended slicing and negative stop value problem Chris Angelico <rosuav@gmail.com> - 2011-08-20 20:53 +0100
Re: extended slicing and negative stop value problem Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2011-08-21 06:40 +1000
Re: extended slicing and negative stop value problem Max <maxmoroz@gmail.com> - 2011-08-21 10:27 -0700
Re: extended slicing and negative stop value problem Chris Rebert <clp2@rebertia.com> - 2011-08-21 15:16 -0700
| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2011-08-20 19:29 +0100 |
| Subject | Re: extended slicing and negative stop value problem |
| Message-ID | <mailman.270.1313864985.27778.python-list@python.org> |
On Sat, Aug 20, 2011 at 7:20 PM, Max Moroz <maxmoroz@gmail.com> wrote: > Would it be a good idea to change Python definition so that a[10, -1, -1] > referred to the elements starting with position 10, going down to the > beginning? Well, first off I think it's a dangerous idea to change semantics of something like that. I can see your use case, but I think that what you want is covered by simply omitting the stop marker: >>> a="qwertyuiopasdfghjklzxcvbnm" >>> a[10:1:-1] 'apoiuytre' >>> a[10:0:-1] 'apoiuytrew' >>> a[10::-1] 'apoiuytrewq' If you're using a variable for the stop value, you just need to set it to an explicit None if it would fall negative: >>> a[10:None:-1] 'apoiuytrewq' Hope that helps! ChrisA
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| From | Max <maxmoroz@gmail.com> |
|---|---|
| Date | 2011-08-20 11:52 -0700 |
| Message-ID | <9c3643a8-ba91-4b0b-8144-f4a6260d6cf0@j14g2000prh.googlegroups.com> |
| In reply to | #11924 |
On Aug 20, 11:29 am, Chris Angelico <ros...@gmail.com> wrote:
> If you're using a variable for the stop value, you just need to set it
> to an explicit None if it would fall negative:
>
> >>> a[10:None:-1]
>
That doesn't work if it's set in a loop or if it's calculated as a
formula. For example, this very simple code doesn't work because of
the "-1 problem".
# find the longest substring that reads the same left to right and
right to left
for substr_length in range(len(input),0,-1):
for starting_pos in range(len(input)-substr_length+1):
ending_pos = starting_pos + substr_length - 1
if input[starting_pos:ending_pos+1] == input[ending_pos :
starting_pos-1 : -1]:
print(input[starting_pos:ending_pos+1])
exit(0)
Of course you can rewrite it, but it becomes quite ugly.
(Not to mention, people who learn the language would not always know
this, and will end up with a bug.)
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| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2011-08-20 20:53 +0100 |
| Message-ID | <mailman.271.1313870035.27778.python-list@python.org> |
| In reply to | #11927 |
On Sat, Aug 20, 2011 at 7:52 PM, Max <maxmoroz@gmail.com> wrote:
> That doesn't work if it's set in a loop or if it's calculated as a
> formula. For example, this very simple code doesn't work because of
> the "-1 problem".
>
Right, which is what I meant by setting it to an explicit None:
if input[starting_pos:ending_pos+1] == input[ending_pos :
starting_pos-1 if starting_pos >= 0 else None : -1]:
You're right that it starts to get ugly, though.
Of course, there are other ways to find the longest palindromic
substring in a string:
# I wouldn't bother counting a one-character "palindrome"
for substr_length in range(len(input),1,-1):
for starting_pos in range(len(input)-substr_length+1):
ending_pos = starting_pos + substr_length - 1
testme = input[starting_pos:ending_pos+1]
if testme == testme[::-1]:
print(testme)
exit(0)
That is, snip out the string and then reverse that snipped piece,
rather than reverse-slicing from the original. This doesn't solve the
issue of slicing backwards with variable halts, though.
ChrisA
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| From | Steven D'Aprano <steve+comp.lang.python@pearwood.info> |
|---|---|
| Date | 2011-08-21 06:40 +1000 |
| Message-ID | <4e501ba1$0$29970$c3e8da3$5496439d@news.astraweb.com> |
| In reply to | #11924 |
Pardon me for breaking threading, but I don't have Max's original post. On Sat, Aug 20, 2011 at 7:20 PM, Max Moroz <maxmoroz@gmail.com> wrote: > Would it be a good idea to change Python definition so that a[10, -1, -1] I presume you mean slice notation a[10:-1:-1]. > referred to the elements starting with position 10, going down to the > beginning? No, almost certainly not. Such a change would break backwards compatibility, and so would only be allowed under very unusual circumstances: the current behaviour would have to be a major problem, or the new behaviour a huge benefit, or both, to make up for: (1) the extra work needed to change the behaviour (probably involving a "from __future__ import ..." feature for the first version or two); (2) breaking people's existing code; and (3) forcing people to learn the new behaviour and unlearn the old. Even if the old behaviour is "wrong", the work needed to fix it may be more than the benefit. If this was going to be "fixed", the time was probably about three years ago, when Python3 was just starting. Now such a change will probably need to wait for the hypothetical Python 4000. > This would require disabling the "negative stop value means counting from > the end of the array" magic whenever the step value is negative. Which will hurt people who expect the current behaviour: >>> a[8:-8:-1] [8, 7, 6, 5, 4, 3] > The reason for this idea is that many people (me including) try to use > extended slices with negative step values, only to realize that they are > messed up. For example, if your stop value is reduced in a loop from a > positive number to -1, the behavior breaks whenever it hits -1. Yes, negative step values are unintuitive, especially if the step is not -1. The solution is, "Don't do that then!". The usual advice is to do your slicing twice, reversing it the second time: a[0:11][::-1] # Instead of a[10:-1:-1], which looks like it should work, but doesn't. (or use the reversed() built-in instead of the second slice), or to write a helper function to adjust the indexes and get whatever behaviour you like. Hint: >>> a[10:-11:-1] [9, 8, 7, 6, 5, 4, 3, 2, 1, 0] -- Steven
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| From | Max <maxmoroz@gmail.com> |
|---|---|
| Date | 2011-08-21 10:27 -0700 |
| Message-ID | <7488461a-de1f-4e7c-ba7f-a15d85896e08@y39g2000prd.googlegroups.com> |
| In reply to | #11931 |
On Aug 20, 1:40 pm, Steven D'Aprano <steve +comp.lang.pyt...@pearwood.info> wrote: > Pardon me for breaking threading, but I don't have Max's original post. Not sure why; I also can't see it! I'll copy it at the end just in case. > On Sat, Aug 20, 2011 at 7:20 PM, Max Moroz <maxmo...@gmail.com> wrote: > > Would it be a good idea to change Python definition so that a[10, -1, -1] > > I presume you mean slice notation a[10:-1:-1]. > > > referred to the elements starting with position 10, going down to the > > beginning? > > If this was going to be "fixed", the time was probably > about three years ago, when Python3 was just starting. Now such a change > will probably need to wait for the hypothetical Python 4000. Yeah, I was surprised that it didn't bother anyone.. > The usual advice is to do your slicing twice, reversing it the second time: > > a[0:11][::-1] > # Instead of a[10:-1:-1], which looks like it should work, but doesn't. It works nicely, but it is 1.3 times slower in my code (I am surprised the interpreter doesn't optimize this).
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| From | Chris Rebert <clp2@rebertia.com> |
|---|---|
| Date | 2011-08-21 15:16 -0700 |
| Message-ID | <mailman.289.1313964991.27778.python-list@python.org> |
| In reply to | #11947 |
On Sun, Aug 21, 2011 at 10:27 AM, Max <maxmoroz@gmail.com> wrote: > On Aug 20, 1:40 pm, Steven D'Aprano <steve > +comp.lang.pyt...@pearwood.info> wrote: >> On Sat, Aug 20, 2011 at 7:20 PM, Max Moroz <maxmo...@gmail.com> wrote: >> > Would it be a good idea to change Python definition so that a[10, -1, -1] >> >> I presume you mean slice notation a[10:-1:-1]. >> >> > referred to the elements starting with position 10, going down to the >> > beginning? <snip> >> The usual advice is to do your slicing twice, reversing it the second time: >> >> a[0:11][::-1] >> # Instead of a[10:-1:-1], which looks like it should work, but doesn't. > > It works nicely, but it is 1.3 times slower in my code (I am surprised > the interpreter doesn't optimize this). That would require CPython to assume certain slicing semantics for all types (which it can't) or to check for this very specific case at runtime (which would slow down all other [list] slicing operations). A smarter implementation such as PyPy could indeed theoretically optimize this case though. Cheers, Chris
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