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logging time format millisecond precision decimalsign

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  logging time format millisecond precision decimalsign "Alex van der Spek" <zdoor@xs4all.nl> - 2012-07-20 15:00 +0200
    Re: logging time format millisecond precision decimalsign Peter Otten <__peter__@web.de> - 2012-07-20 16:31 +0200
    Re: logging time format millisecond precision decimalsign David Bolen <db3l.net@gmail.com> - 2012-07-20 14:50 -0400

#25692 — logging time format millisecond precision decimalsign

I use this formatter in logging:

formatter = logging.Formatter(fmt='%(asctime)s \t %(name)s \t %(levelname)s
\t %(message)s')

Sample output:

2012-07-19 21:34:58,382   root   INFO   Removed - C:\Users\ZDoor\Documents

The time stamp has millisecond precision but the decimal separator is a
comma.

Can I change the comma (,) into a period (.) and if so how?

Thanks in advance,
Alex van der Spek

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#25694

Alex van der Spek wrote:

> I use this formatter in logging:
> 
> formatter = logging.Formatter(fmt='%(asctime)s \t %(name)s \t
> %(levelname)s \t %(message)s')
> 
> Sample output:
> 
> 2012-07-19 21:34:58,382   root   INFO   Removed - C:\Users\ZDoor\Documents
> 
> The time stamp has millisecond precision but the decimal separator is a
> comma.
> 
> Can I change the comma (,) into a period (.) and if so how?

I think you have to subclass Formatter.formatTime(). Here's a monkey-
patching session to get you started:

>>> import logging
>>> logging.basicConfig(format="%(asctime)s")
>>> logging.getLogger().error("foo")
2012-07-20 16:17:39,364
>>> _formatTime = logging.Formatter.formatTime
>>> def formatTime(*args):
...     return _formatTime(*args).replace(",", ".")
...
>>> logging.Formatter.formatTime = formatTime
>>> logging.getLogger().error("foo")
2012-07-20 16:20:20.838

See also

http://docs.python.org/dev/py3k/library/logging.html#logging.Formatter.formatTime

"""
Changed in version 3.3: Previously, the default ISO 8601 format was hard-
coded as in this example: 2010-09-06 22:38:15,292 where the part before the 
comma is handled by a strptime format string ('%Y-%m-%d %H:%M:%S'), and the 
part after the comma is a millisecond value. Because strptime does not have 
a format placeholder for milliseconds, the millisecond value is appended 
using another format string, '%s,%03d' – and both of these format strings 
have been hardcoded into this method. With the change, these strings are 
defined as class-level attributes which can be overridden at the instance 
level when desired. The names of the attributes are default_time_format (for 
the strptime format string) and default_msec_format (for appending the 
millisecond value).
"""

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#25703

"Alex van der Spek" <zdoor@xs4all.nl> writes:

> I use this formatter in logging:
>
> formatter = logging.Formatter(fmt='%(asctime)s \t %(name)s \t %(levelname)s
> \t %(message)s')
>
> Sample output:
>
> 2012-07-19 21:34:58,382   root   INFO   Removed - C:\Users\ZDoor\Documents
>
> The time stamp has millisecond precision but the decimal separator is a
> comma.
>
> Can I change the comma (,) into a period (.) and if so how?

I do it by:

  1. Replacing the default date format string to exclude ms.
  2. Including %(msecs)03d in the format string where appropriate.  Using 'd'
     instead of s truncates rather than shows the full float value.

So in your case, I believe that changing your formatter creation to:

  formatter = logging.Formatter(fmt='%(asctime)s.%(msecs)03d \t %(name)s \t %(levelname)s \t %(message)s', '%Y-%m-%d %H:%M:%S')

should work.  This uses the same date format as the default, but
without ms, though of course you could also opt to make any other date
format you prefer.

-- David

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