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Re: Count each unique element in list of lists

Started byChris Angelico <rosuav@gmail.com>
First post2013-11-09 06:44 +1100
Last post2013-11-09 06:44 +1100
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  Re: Count each unique element in list of lists Chris Angelico <rosuav@gmail.com> - 2013-11-09 06:44 +1100

#58844 — Re: Count each unique element in list of lists

FromChris Angelico <rosuav@gmail.com>
Date2013-11-09 06:44 +1100
SubjectRe: Count each unique element in list of lists
Message-ID<mailman.2244.1383939900.18130.python-list@python.org>
On Sat, Nov 9, 2013 at 6:28 AM, Yaşar Arabacı <yasar11732@gmail.com> wrote:
> I want to write a code that
> shows that each elem in sublists of result on appears once in whole
> sublist in order to add it to
> my doctest.

So, to clarify the problem: You want to ensure that every element
occurs exactly once, neither more nor less? And you have a guarantee
that the lists and sublists have a specific nesting depth? Try this:

[sorted((x for l in result for x in l)) for result in results]

Flattens and sorts the lists.

[sorted((x for l in result for x in l))==list(range(1,10)) for result
in results]

Flattens, sorts, and compares with a template list (which in this case
is [1, 2, 3, 4, 5, 6, 7, 8, 9] from range()).

ChrisA

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