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Re: How to do integers to binary lists and back

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  Re: How to do integers to binary lists and back John Pote <johnhpote@o2.co.uk> - 2015-05-30 00:18 +0100

#91510 — Re: How to do integers to binary lists and back

On 21/05/2015 23:31, MRAB wrote:
> On 2015-05-21 23:20, John Pote wrote:
>> Hi everyone.
>> I recently had the problem of converting from an integer to its
>> representation as a list of binary bits, each bit being an integer 1 or
>> 0, and vice versa. E.G.
>> 0x53
>> becomes
>> [ 0, 1, 0, 1, 0, 0, 1, 1 ]
>>
>> This I wanted to do for integers of many tens, if not hundreds, of bits.
>> Python very nicely expands integers to any size required, great feature.
>>
>> Just wondered if there was a neat way of doing this without resorting to
>> a bit bashing loop.
>>
>> Looking forward to some interesting answers,
>> John
>>
>>
> I don't know how efficient you want it to be, but:
>
> >>> number = 0x53
> >>> bin(number)
> '0b1010011'
> >>> bin(number)[2 : ]
> '1010011'
> >>> list(map(int, bin(number)[2 : ]))
> [1, 0, 1, 0, 0, 1, 1]
>
Thanks for the replies. Interesting that the offered solutions involve 
converting to a binary text string and then the individual chars back to 
ints. I had thought this would be a route to solve this problem but it 
seemed a bit 'heavy' hence I thought it worthwhile asking the question.

My solution to converting a list of 1s and 0s back to an int is
         listLen = len( binList )
         n = sum( [ binList[i]*( 2**(listLen-1 - i) ) for i in 
range(listLen)] )

In response to Ben Finney's question, I haven't done homework for 40 
years! Genuine problem, I had decided that the clearest way to write the 
algorithm I was working on was to use lists of 1s and 0s rather than 
normal ints.

Thanks for the help,
John

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