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Re: Verification of bank number using modulus 11

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  Re: Verification of bank number using modulus 11 Morten Engvoldsen <mortenengv@gmail.com> - 2013-02-20 10:24 +0100

#39328 — Re: Verification of bank number using modulus 11

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Hi,
Thanks for below code:
After this code:

isbn = isbn[:-1]
if len(isbn) != 10:
  return False

Add:

if isbn[4:6] == "00":
    isbn = isbn[6:]

It is working exactly how it should :)
I didn't even change that part .  The zip function automatically truncates
to the length of the shorter input sequence.

Thanks a lot again :)

Have a nice day..


On Tue, Feb 19, 2013 at 11:59 PM, Morten Engvoldsen <mortenengv@gmail.com>wrote:

> Hi Team,
> Thanks for the code.
>  I have altered the code with below code, it is able to validate the
> number now,
>
> def calc_checkdigit(isbn):
> isbn = isbn.replace(".", "")
> check_digit = int(isbn[-1])
> isbn = isbn[:-1]
> if len(isbn) != 10:
>   return False
> weights = [5, 4, 3, 2, 7, 6, 5, 4, 3, 2]
> result = sum(w * (int(x)) for w, x in zip(weights, isbn))
> remainder = result % 11
> if remainder == 0:
>    check = 0
> else:
>    check = 11 - remainder
> return check == check_digit
>
> calc_checkdigit(""8601.11.**17947"")
>
>
> But can you tell me how could i implement below
>
> "If digits 5 and 6 of the account number are zeros, the check digit is
> calculated on the 7, 8, 9 and 10th digit of the account number."
>
> which means if account number is "8601.00.**17947" then check digit is
> calculate as
>
>  result = (1*5) + (7*4)+ (9*3)+(4*2)
>
> remainder = result % 11
>
> check_digit = 11 - remainder
>
> Can you tell me how can i implement this ?
>
>
>
>
>
>
>

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