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Prepending string "@" to usernames

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  Prepending string "@" to usernames Thomas Murphy <thomasmurphymusic@gmail.com> - 2013-05-24 18:53 -0400
    Re: Prepending string "@" to usernames Larry Hudson <orgnut@yahoo.com> - 2013-05-24 20:24 -0700

#45922 — Prepending string "@" to usernames

Hi beloved list,

I'm having a dumb and SO doesn't seem to have this one answered. I was
sent a long list of instagram usernames to tag for a nightlife
announcement in this format(not real names(i hope))

cookielover93
TheGermanHatesSaurkraut
WhatsThatBoy932834

I'd like to turn this raw text into a list and prepend the @ symbol to
the front of each one, so they're good to go for pasting without me
having to manually add the @ to each one.

Here's where I got to:


raw_address = "cookielover93 TheGermanHatesSaurkraut WhatsThatBoy932834"
address_library = [raw_address.split()]
print address_library

for address in address_library:
    final_address = "@" + str(address)
print final_address


However my output is:

[['cookielover93', 'TheGermanHatesSaurkraut', 'WhatsThatBoy932834']]
@['cookielover93', 'TheGermanHatesSaurkraut', 'WhatsThatBoy932834']


I know I'm iterating wrong. May I ask how?

--
Sincerely,
Thomas Murphy
Code Ninja
646.957.6115

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#45946

On 05/24/2013 03:53 PM, Thomas Murphy wrote:

<snip>

> Here's where I got to:
>
>
> raw_address = "cookielover93 TheGermanHatesSaurkraut WhatsThatBoy932834"
> address_library = [raw_address.split()]
> print address_library
>
> for address in address_library:
>      final_address = "@" + str(address)
> print final_address
>
>
> However my output is:
>
> [['cookielover93', 'TheGermanHatesSaurkraut', 'WhatsThatBoy932834']]
> @['cookielover93', 'TheGermanHatesSaurkraut', 'WhatsThatBoy932834']
>
>
> I know I'm iterating wrong. May I ask how?
>
> --
> Sincerely,
> Thomas Murphy
> Code Ninja
> 646.957.6115
>

No, you're not iterating wrong, but you do have two errors:

1:  split() returns a list.  You are putting this list (as a single element) inside a list. 
Drop the square brackets.  Make it:  address_library = raw_address.split()

2:  In your for loop, you want the print _inside_ the loop not outside.  IOW, indent the print 
line.  The way you have it written it will only print the _last_ string.

      -=- Larry -=-

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