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RE: file I/O and arithmetic calculation

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  RE: file I/O and arithmetic calculation Carlos Nepomuceno <carlosnepomuceno@outlook.com> - 2013-05-23 06:15 +0300

#45769 — RE: file I/O and arithmetic calculation

The last line of my noob piece can be improved. So this is it:

### 1strow_average.py ###
#Assuming you have CSV (comma separated values) files such as:
#1.txt = '0,1,2,3,4,5,6,7,8,9\n' \
#        '10,11,12,13,14,15,16,17,18,19\n' \
#        '20,21,22,23,24,25,26,27,28,29\n' ...
#
# Usage: contents[file][row][column]
# contents[0]       : file '1.txt'
# contents[1][2]    : 3rd row of file '2.txt'
# contents[3][4][5] : value on the 6th column of 5th row of file '4.txt'
# len(contents)     : quantity of files
# len(contents[4])  : quantity of lines in file '5.txt'
# len(contents[4][0]: quantity of values in the 1st line of file '5.txt'

filenames = ['1.txt', '2.txt', '3.txt', '4.txt', '5.txt']
contents  = [[[int(z) for z in y.split(',')] for y in open(x).read().split()] for x in filenames]
s1c  = [sum([r[0] for r in f]) for f in contents]
a1r  = [sum(f[0])/float(len(f[0])) for f in contents]
print '\n'.join(['File "{}" has 1st row average = {:.2f}'.format(n,a1r[i]) for i,n in enumerate(filenames) if s1c[i]==50]) 		 	   		  

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