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Groups > comp.lang.python > #54479 > unrolled thread
| Started by | Vlastimil Brom <vlastimil.brom@gmail.com> |
|---|---|
| First post | 2013-09-20 17:47 +0200 |
| Last post | 2013-09-20 17:47 +0200 |
| Articles | 1 — 1 participant |
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Re: Antispam measures circumventing Vlastimil Brom <vlastimil.brom@gmail.com> - 2013-09-20 17:47 +0200
| From | Vlastimil Brom <vlastimil.brom@gmail.com> |
|---|---|
| Date | 2013-09-20 17:47 +0200 |
| Subject | Re: Antispam measures circumventing |
| Message-ID | <mailman.187.1379692075.18130.python-list@python.org> |
2013/9/20 Jugurtha Hadjar <jugurtha.hadjar@gmail.com>: > Hello, > # I posted this on the tutor list, but my message wasn't displayed > I shared some assembly code (microcontrollers) and I had a comment wit my > e-mail address for contact purposes. > Supposing my name is John Doe and the e-mail is john.doe@hotmail.com, my > e-mail was written like this: > REMOVEMEjohn.doSPAMeSPAM@REMOVEMEhotmail.com' > With a note saying to remove the capital letters. > Now, I wrote this : > for character in my_string: > ... if (character == character.upper()) and (character !='@') and > (character != '.'): > ... my_string = my_string.replace(character,'') > And the end result was john.doe@hotmail.com. > Is there a better way to do that ? Without using regular expressions (Looked > *really* ugly and it doesn't really make sense, unlike the few lines I've > written, which are obvious even to a beginner like me). > I obviously don't like SPAM, but I just thought "If I were a spammer, how > would I go about it". > Eventually, some algorithm of detecting the john<dot>doe<at>hotmail<dot>com > must exist. > retrieve the original e-mail address? Maybe a function with no inverse > function ? Generating an image that can't be converted back to text, etc.. > If this is off-topic, you can just answer the "what is a better way to do > that" part. > > Thanks, > -- > ~Jugurtha Hadjar, > -- > https://mail.python.org/mailman/listinfo/python-list Hi, is the regex really that bad for such simple replacement? >>> re.sub(r"[A-Z]", "", "REMOVEMEjohn.doSPAMeSPAM@REMOVEMEhotmail.com") 'john.doe@hotmail.com' Alternatively, you can use a check with the string method isupper(): >>> "".join(char for char in "REMOVEMEjohn.doSPAMeSPAM@REMOVEMEhotmail.com" if not char.isupper()) 'john.doe@hotmail.com' or using a special form of str.translate() >>> "REMOVEMEjohn.doSPAMeSPAM@REMOVEMEhotmail.com".translate(None, "ABCDEFGHIJKLMNOPQRSTUVWXYZ") 'john.doe@hotmail.com' which is the same like: >>> import string >>> "REMOVEMEjohn.doSPAMeSPAM@REMOVEMEhotmail.com".translate(None, string.ascii_uppercase) 'john.doe@hotmail.com' Another possibility would be to utilise ord(...) >>> "".join(char for char in "REMOVEMEjohn.doSPAMeSPAM@REMOVEMEhotmail.com" if ord(char) not in range(65, 91)) 'john.doe@hotmail.com' >>> Well, maybe there are other possibilities, these above are listed roughly in the order of my personal preference. Of course, others may differ... hth, vbr
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