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Groups > comp.lang.python > #5850 > unrolled thread
| Started by | ErichCart ErichCart <erichcart@gmail.com> |
|---|---|
| First post | 2011-05-20 04:37 -0700 |
| Last post | 2011-05-20 21:57 +1000 |
| Articles | 3 — 3 participants |
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Python sets which support multiple same elements ErichCart ErichCart <erichcart@gmail.com> - 2011-05-20 04:37 -0700
RE: Python sets which support multiple same elements Andreas Tawn <andreas.tawn@ubisoft.com> - 2011-05-20 13:53 +0200
Re: Python sets which support multiple same elements Chris Angelico <rosuav@gmail.com> - 2011-05-20 21:57 +1000
| From | ErichCart ErichCart <erichcart@gmail.com> |
|---|---|
| Date | 2011-05-20 04:37 -0700 |
| Subject | Python sets which support multiple same elements |
| Message-ID | <f7760e6f-b176-4c13-8285-08d7689ece02@f31g2000pri.googlegroups.com> |
Many times when I am writing some program in python, I notice that I
could transform my list into set, then use the set methods like union,
intersection, set equality etc. , and it will solve my problem easily.
But then I realize that if I transform my list into set, it will
remove duplicates of elements in the list and so I will lose
information from my original list.
For example, I was writing a program to detect whether two strings are
anagrams of each other. I had to write it like this:
def isAnagram(w1, w2):
w2=list(w2)
for c in w1:
if c not in w2:
return False
else:
w2.remove(c)
return True
But if there was a data structure in python which supported duplicate
elements(lets call it dset), then I could just write:
def inAnagram(w1,w2):
return dset(w1)==dset(w2)
Example of some dset methods:
{1,2,3,3} intersection {4,1,2,3,3,3} == {1,2,3,3}
{1,2,3,3} union {4,1,2,3,3,3} == {1,2,3,3,3,4}
{4,1,2,3,3,3} difference {1,2,3,3} == {4,3}
Do you think that it would be a good idea to add this kind of data
structure to python? Or did I overlook some other easy way to solve
this kind of problems?
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| From | Andreas Tawn <andreas.tawn@ubisoft.com> |
|---|---|
| Date | 2011-05-20 13:53 +0200 |
| Message-ID | <mailman.1838.1305892439.9059.python-list@python.org> |
| In reply to | #5850 |
> For example, I was writing a program to detect whether two strings are
> anagrams of each other. I had to write it like this:
>
> def isAnagram(w1, w2):
> w2=list(w2)
> for c in w1:
> if c not in w2:
> return False
> else:
> w2.remove(c)
> return True
>
> But if there was a data structure in python which supported duplicate
> elements(lets call it dset), then I could just write:
>
> def inAnagram(w1,w2):
> return dset(w1)==dset(w2)
>
> Example of some dset methods:
> {1,2,3,3} intersection {4,1,2,3,3,3} == {1,2,3,3}
> {1,2,3,3} union {4,1,2,3,3,3} == {1,2,3,3,3,4}
> {4,1,2,3,3,3} difference {1,2,3,3} == {4,3}
>
> Do you think that it would be a good idea to add this kind of data
> structure to python? Or did I overlook some other easy way to solve
> this kind of problems?
Just to do the anagram problem you could do...
def isAnagram(w1, w2):
return sorted(w1) == sorted(w2)
To do the set-like operations, I guess that unless there's some itertools witchcraft available, you'd have to make your own dset type that inherits from list. Then you can define your own intersection/union etc. methods.
Cheers,
Drea
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| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2011-05-20 21:57 +1000 |
| Message-ID | <mailman.1839.1305892667.9059.python-list@python.org> |
| In reply to | #5850 |
On Fri, May 20, 2011 at 9:37 PM, ErichCart ErichCart <erichcart@gmail.com> wrote: > For example, I was writing a program to detect whether two strings are > anagrams of each other. I had to write it like this: > > def isAnagram(w1, w2): > w2=list(w2) > for c in w1: > if c not in w2: > return False > else: > w2.remove(c) > return True You may find it helpful to simply sort the lists, keeping them as lists. If they're anagrams of each other, their sorted versions will be equal. Chris Angelico
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