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Socket programming

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  Socket programming pramod gowda <pramod.sp78@gmail.com> - 2015-01-03 03:43 -0800
    Re: Socket programming Chris Angelico <rosuav@gmail.com> - 2015-01-03 22:56 +1100
      Re: Socket programming pramod gowda <pramod.sp78@gmail.com> - 2015-01-03 04:25 -0800
        Re: Socket programming Chris Angelico <rosuav@gmail.com> - 2015-01-03 23:38 +1100
          Re: Socket programming pramod gowda <pramod.sp78@gmail.com> - 2015-01-03 05:22 -0800
    Re: Socket programming mm0fmf <none@mailinator.com> - 2015-01-03 15:09 +0000
      Re: Socket programming pramod gowda <pramod.sp78@gmail.com> - 2015-01-03 07:15 -0800
        Re: Socket programming Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2015-01-04 02:57 +1100
          Re: Socket programming pramod gowda <pramod.sp78@gmail.com> - 2015-01-03 08:10 -0800
    Re: Socket programming Dan Stromberg <drsalists@gmail.com> - 2015-01-03 09:16 -0800
      Re: Socket programming Jorgen Grahn <grahn+nntp@snipabacken.se> - 2015-01-04 18:12 +0000

#83152 — Socket programming

Hi i am learning socket programming,

client code:

import socket

client_socket=socket.socket()
server_address='192.168.2.2'
server_port= 80
print("hello")
client_socket.connect((server_address,server_port))
print("hello")
data=client_socket.recv(1024)
print(data)
client_socket.close()

server code:
import socket

server_socket=socket.socket()
server_name='192.168.2.2'
server_port= 80
server_socket.bind((server_name,server_port))
server_socket.listen(1)

while True:
    print("hello")
    c,address=server_socket.accept()
    print("we got connection from:",address)
    c.send("hello,hw ru")
    c.close()




I am not getting the output, i am using windows 7 OS..
please  check and give me the solution.

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#83154

On Sat, Jan 3, 2015 at 10:43 PM, pramod gowda <pramod.sp78@gmail.com> wrote:
> I am not getting the output, i am using windows 7 OS..
> please  check and give me the solution.

Windows 7 - that's part of the story. What version of Python are you
using? Is 192.168.2.2 the correct IP address? What happens when you
run these? Do you get exceptions?

ChrisA

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#83157

On Saturday, January 3, 2015 5:26:27 PM UTC+5:30, Chris Angelico wrote:
> On Sat, Jan 3, 2015 at 10:43 PM, pramod gowda <pramod.sp78@gmail.com> wrote:
> > I am not getting the output, i am using windows 7 OS..
> > please  check and give me the solution.
> 
> Windows 7 - that's part of the story. What version of Python are you
> using? Is 192.168.2.2 the correct IP address? What happens when you
> run these? Do you get exceptions?
> 
> ChrisA

Hi chris.


I am using python 3.4.2
I don get any exceptions,
but wn i run the code,i don see any connections, IP address is given as my system IP.

 c,address=server_socket.accept() in server.py..if am trying to print something,it fails

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#83158

On Sat, Jan 3, 2015 at 11:25 PM, pramod gowda <pramod.sp78@gmail.com> wrote:
> I am using python 3.4.2
> I don get any exceptions,
> but wn i run the code,i don see any connections, IP address is given as my system IP.

What does the client say?

ChrisA

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#83159

On Saturday, January 3, 2015 6:08:28 PM UTC+5:30, Chris Angelico wrote:
> On Sat, Jan 3, 2015 at 11:25 PM, pramod gowda <pramod.sp78@gmail.com> wrote:
> > I am using python 3.4.2
> > I don get any exceptions,
> > but wn i run the code,i don see any connections, IP address is given as my system IP.
> 
> What does the client say?
> 
> ChrisA

After  c,address=server_socket.accept()  ,this line of code,nothing s being executed.

example i am just trying to print "Hello"
thts also not being printed

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#83163

On 03/01/2015 11:43, pramod gowda wrote:
> server_socket=socket.socket()
> server_name='192.168.2.2'
> server_port= 80
> server_socket.bind((server_name,server_port))
> server_socket.listen(1)

I don't do much Python on Windows but do you have the necessary access 
rights to open a listening socket on port 80? Don't you need to run this 
with Administrator rights?

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#83164

On Saturday, January 3, 2015 8:39:26 PM UTC+5:30, mm0fmf wrote:
> On 03/01/2015 11:43, pramod gowda wrote:
> > server_socket=socket.socket()
> > server_name='192.168.2.2'
> > server_port= 80
> > server_socket.bind((server_name,server_port))
> > server_socket.listen(1)
> 
> I don't do much Python on Windows but do you have the necessary access 
> rights to open a listening socket on port 80? Don't you need to run this 
> with Administrator rights?

HI, i m doing n personal laptop.
so i think i ve rights to open a listening socket,could u pls tell me hw can i check it?

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#83165

pramod gowda wrote:

> HI, i m doing n personal laptop.
> so i think i ve rights to open a listening socket,could u pls tell me hw
> can i check it?

Is your keyboard broken? There are a lot of missing characters in your
sentences. You're going to have a lot of trouble programming with a broken
keyboard.

As far as sockets, this is a Python discussion group, not Windows experts.
Try googling for more information and see if that helps:

https://duckduckgo.com/?q=windows%20permission%20to%20open%20sockets




-- 
Steven

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#83166

On Saturday, January 3, 2015 9:27:20 PM UTC+5:30, Steven D'Aprano wrote:
> pramod gowda wrote:
> 
> > HI, i m doing n personal laptop.
> > so i think i ve rights to open a listening socket,could u pls tell me hw
> > can i check it?
> 
> Is your keyboard broken? There are a lot of missing characters in your
> sentences. You're going to have a lot of trouble programming with a broken
> keyboard.
> 
> As far as sockets, this is a Python discussion group, not Windows experts.
> Try googling for more information and see if that helps:
> 
> https://duckduckgo.com/?q=windows%20permission%20to%20open%20sockets
> 
> 
> 
> 
> -- 
> Steven

Hi Steven,


Sorry for using short words while posting,I am using python in windows7 with Python ver 3.4.2 for socket program,so i am asking for help.

Thanks
Pramod SP

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#83168

On Sat, Jan 3, 2015 at 3:43 AM, pramod gowda <pramod.sp78@gmail.com> wrote:
> Hi i am learning socket programming,

This "works" on Linux Mint 17.1.

Server:
#!/usr/local/cpython-3.4/bin/python

import socket

server_socket = socket.socket()
#server_name = '192.168.2.2'
server_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
server_name = 'localhost'
server_port = 8080
server_socket.bind((server_name, server_port))
server_socket.listen(1)

while True:
    print("hello")
    c,address = server_socket.accept()
    print("we got connection from:",address)
    c.send(b"hello,hw ru")
    c.close()


client:
#!/usr/local/cpython-3.4/bin/python

import socket

client_socket = socket.socket()
#server_address='192.168.2.2'
server_address = 'localhost'
server_port = 8080
print("hello")
client_socket.connect((server_address,server_port))
print("hello")
data=client_socket.recv(1024)
print(data)
client_socket.close()


But note that if you send 10 bytes into a socket, it could be received
as two chunks of 5, or other strangeness. So you should frame your
data somehow - adding crlf to the end of your send's is one simple
way.  There are multiple ways of dealing with this.  Here's one:
http://stromberg.dnsalias.org/~strombrg/bufsock.html with links to
others.

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#83218

On Sat, 2015-01-03, Dan Stromberg wrote:
> On Sat, Jan 3, 2015 at 3:43 AM, pramod gowda <pramod.sp78@gmail.com> wrote:
...

> data=client_socket.recv(1024)
> print(data)
> client_socket.close()
>
>
> But note that if you send 10 bytes into a socket, it could be received
> as two chunks of 5, or other strangeness. So you should frame your
> data somehow - adding crlf to the end of your send's is one simple
> way.

I like to think of it as "defining the protocol" rather than "framing
your data".  But it ends up as the same thing: making sure each end
knows when it should stop looking for more data and start /acting/ on
it.

And yes, you can't do much with a TCP soocket without setting up these
rules. It's important to see that noone does it /for/ you.

/Jorgen

-- 
  // Jorgen Grahn <grahn@  Oo  o.   .     .
\X/     snipabacken.se>   O  o   .

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