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| Started by | Dave Angel <d@davea.name> |
|---|---|
| First post | 2012-09-29 21:41 -0400 |
| Last post | 2012-09-29 21:41 -0400 |
| Articles | 1 — 1 participant |
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Re: Compairing filenames in a list Dave Angel <d@davea.name> - 2012-09-29 21:41 -0400
| From | Dave Angel <d@davea.name> |
|---|---|
| Date | 2012-09-29 21:41 -0400 |
| Subject | Re: Compairing filenames in a list |
| Message-ID | <mailman.1659.1348969290.27098.python-list@python.org> |
On 09/29/2012 09:27 PM, Kevin Anthony wrote: > I have a list of filenames, and i need to find files with the same > name, different extensions, and split that into tuples. does anyone have > any suggestions on an easy way to do this that isn't O(n^2)? > > Sure, collect them in a collections.defaultdict Use basename for the key, and a list of names as the data item. if that's not good enough, show us your code, and why it doesn't work, and tell us what version of Python you're using. -- DaveA
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