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Trying to understand html.parser.HTMLParser

Started byAndrew Berg <bahamutzero8825@gmail.com>
First post2011-05-15 15:45 -0500
Last post2011-05-15 15:45 -0500
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  Trying to understand html.parser.HTMLParser Andrew Berg <bahamutzero8825@gmail.com> - 2011-05-15 15:45 -0500

#5445 — Trying to understand html.parser.HTMLParser

FromAndrew Berg <bahamutzero8825@gmail.com>
Date2011-05-15 15:45 -0500
SubjectTrying to understand html.parser.HTMLParser
Message-ID<mailman.1599.1305492338.9059.python-list@python.org>
I'm trying to understand why HMTLParser.feed() isn't returning the whole
page. My test script is this:

import urllib.request
import html.parser
class MyHTMLParser(html.parser.HTMLParser):   
    def handle_starttag(self, tag, attrs):
        if tag == 'a' and attrs:
            print(tag,'-',attrs)

url = 'http://x264.nl/x264/?dir=./64bit/8bit_depth'
page = urllib.request.urlopen(url).read()
parser = MyHTMLParser()
parser.feed(str(page))

I can do print(page) and get the entire HTML source, but
parser.feed(str(page)) only spits out the information for the top links
and none of the "revisionxxxx" links. Ultimately, I just want to find
the name of the first "revisionxxxx" link (right now it's
"revision1995", when a new build is uploaded it will be "revision2000"
or whatever). I figure this is a relatively simple page; once I
understand all of this, I can move on to more complicated pages.

I've searched Google, but everything I find is either outdated, a
recommendation for some external module (I don't need to do anything too
fancy and most modules don't completely support Python 3 anyway) or is
just a code snippet with no real explanation. I had a book that
explained this, but I had to return it to the library (and I'll have to
get back in line to check it out again).

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