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Rounding a number

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  Rounding a number Seymore4Head <Seymore4Head@Hotmail.invalid> - 2015-04-30 15:49 -0400
    Re: Rounding a number Thijs Engels <thijs@buckazoids.com> - 2015-04-30 22:00 +0200
      Re: Rounding a number Seymore4Head <Seymore4Head@Hotmail.invalid> - 2015-04-30 18:35 -0400
        Re: Rounding a number Dave Angel <davea@davea.name> - 2015-04-30 18:58 -0400
    Re: Rounding a number Mark Lawrence <breamoreboy@yahoo.co.uk> - 2015-04-30 21:08 +0100
    Re: Rounding a number Tony the Tiger <tony@tiger.invalid> - 2015-05-02 21:34 +0000

#89666 — Rounding a number

I have this page book marked.
https://mkaz.com/2012/10/10/python-string-format/

I am getting numbers from sixty thousand to two hundred thousand.
I would like to round them to the nearest thousand.
So 65,253 should read 65,000.
How?

Total=2100
for x in range (10,35):
    count=1000/x
    print ("Foo {:7,.0f} Fighters".format(Total*count))

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#89667

round(65253, -3)

might be what you are looking for...


On Thu, Apr 30, 2015, at 21:49, Seymore4Head wrote:
> I have this page book marked.
> https://mkaz.com/2012/10/10/python-string-format/
> 
> I am getting numbers from sixty thousand to two hundred thousand.
> I would like to round them to the nearest thousand.
> So 65,253 should read 65,000.
> How?
> 
> Total=2100
> for x in range (10,35):
>     count=1000/x
>     print ("Foo {:7,.0f} Fighters".format(Total*count))
> -- 
> https://mail.python.org/mailman/listinfo/python-list

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#89678

On Thu, 30 Apr 2015 22:00:17 +0200, Thijs Engels
<thijs@buckazoids.com> wrote:

>round(65253, -3)
>
>might be what you are looking for...
>
>
>On Thu, Apr 30, 2015, at 21:49, Seymore4Head wrote:
>> I have this page book marked.
>> https://mkaz.com/2012/10/10/python-string-format/
>> 
>> I am getting numbers from sixty thousand to two hundred thousand.
>> I would like to round them to the nearest thousand.
>> So 65,253 should read 65,000.
>> How?
>> 
>> Total=2100
>> for x in range (10,35):
>>     count=1000/x
>>     print ("Foo {:7,.0f} Fighters".format(Total*count))
>> -- 
>> https://mail.python.org/mailman/listinfo/python-list

Thanks

I know there are more than one way to round and answer.  I was hoping
that using the {:7,.0f} formatting had a solution.

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#89680

On 04/30/2015 06:35 PM, Seymore4Head wrote:
> On Thu, 30 Apr 2015 22:00:17 +0200, Thijs Engels
> <thijs@buckazoids.com> wrote:
>
>> round(65253, -3)
>>
>> might be what you are looking for...
>>
>>
>> On Thu, Apr 30, 2015, at 21:49, Seymore4Head wrote:
>>> I have this page book marked.
>>> https://mkaz.com/2012/10/10/python-string-format/
>>>
>>> I am getting numbers from sixty thousand to two hundred thousand.
>>> I would like to round them to the nearest thousand.
>>> So 65,253 should read 65,000.
>>> How?
>>>
>>> Total=2100
>>> for x in range (10,35):
>>>      count=1000/x
>>>      print ("Foo {:7,.0f} Fighters".format(Total*count))
>>> --
>>> https://mail.python.org/mailman/listinfo/python-list
>
> Thanks
>
> I know there are more than one way to round and answer.  I was hoping
> that using the {:7,.0f} formatting had a solution.
>

There are definite tradeoffs, but since you're rounding to integer size, 
the round() function works fine.  If you wanted tenths, you'd have to 
realize that a float (which is binary float) can't represent them 
exactly.  So depending on what further processing you do, you might see 
some effects that would not seem like it worked right.

Using the % or the .format style of formatting works fine, but it gives 
you a string.  You didn't specify that, so people probably assumed you 
wanted numbers.

-- 
DaveA

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#89668

On 30/04/2015 21:00, Thijs Engels wrote:
> On Thu, Apr 30, 2015, at 21:49, Seymore4Head wrote:
>> I have this page book marked.
>> https://mkaz.com/2012/10/10/python-string-format/
>>
>> I am getting numbers from sixty thousand to two hundred thousand.
>> I would like to round them to the nearest thousand.
>> So 65,253 should read 65,000.
>> How?
>>
>> Total=2100
>> for x in range (10,35):
>>      count=1000/x
>>      print ("Foo {:7,.0f} Fighters".format(Total*count))
>> --
>> https://mail.python.org/mailman/listinfo/python-list
 > round(65253, -3)
 >
 > might be what you are looking for...
 >
 >

True, but please don't top post here.  It's no problem on short threads, 
but as they get longer trying to follow when top posting is involved is 
nigh on impossible.

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence

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#89804

On Thu, 30 Apr 2015 15:49:52 -0400, Seymore4Head wrote:

> I have this page book marked.
> https://mkaz.com/2012/10/10/python-string-format/
> 
> I am getting numbers from sixty thousand to two hundred thousand.
> I would like to round them to the nearest thousand.
> So 65,253 should read 65,000.
> How?

One solution, not necessarily the best:

>>> int(round(65253/1000, 0)*1000)
65000


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