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| Started by | Chris Rebert <clp2@rebertia.com> |
|---|---|
| First post | 2012-09-03 01:36 -0700 |
| Last post | 2012-09-03 01:36 -0700 |
| Articles | 1 — 1 participant |
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Re: get the matched regular expression position in string. Chris Rebert <clp2@rebertia.com> - 2012-09-03 01:36 -0700
| From | Chris Rebert <clp2@rebertia.com> |
|---|---|
| Date | 2012-09-03 01:36 -0700 |
| Subject | Re: get the matched regular expression position in string. |
| Message-ID | <mailman.133.1346661375.27098.python-list@python.org> |
On Mon, Sep 3, 2012 at 1:18 AM, contro opinion <contropinion@gmail.com> wrote:
> Subject: get the matched regular expression position in string.
As is often the case in Python, string methods suffice. Particularly
for something so simple, regexes aren't necessary.
> Here is a string :
>
> str1="ha,hihi,aaaaa,ok"
>
> I want to get the position of "," in the str1,Which can count 3,8,14.
Note that Python's indices start at 0. Your example output uses 1-based indices.
> how can I get it in python ?
def find_all(string, substr):
start = 0
while True:
try:
pos = string.index(substr, start)
except ValueError:
break
else:
yield pos
start = pos + 1
str1 = "ha,hihi,aaaaa,ok"
print list(find_all(str1, ",")) #===> [2, 7, 13]
In the future, I recommend reading the documentation for Python's string type:
http://docs.python.org/library/stdtypes.html#string-methods
What opinion are you contrary ("contro") to anyway?
Regards,
Chris
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