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Integer as raw hex string?

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  Integer as raw hex string? Roy Smith <roy@panix.com> - 2012-12-24 10:36 -0500
    Re: Integer as raw hex string? Tim Chase <python.list@tim.thechases.com> - 2012-12-24 09:58 -0600
      Re: Integer as raw hex string? Roy Smith <roy@panix.com> - 2012-12-24 11:21 -0500
    Re: Integer as raw hex string? MRAB <python@mrabarnett.plus.com> - 2012-12-24 18:15 +0000

#35460 — Integer as raw hex string?

I have an integer that I want to encode as a hex string, but I don't 
want "0x" at the beginning, nor do I want "L" at the end if it happened 
to be a long.  The result needs to be something I can pass to int(h, 16) 
to get back my original integer.

The brute force way works:

   h = hex(i)
   assert h.startswith('0x')
   h = h[2:]
   if h.endswith('L'):
       h = h[:-1]

but I'm wondering if there's some built-in call which gives me what I 
want directly.  Python 2.7.

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#35462

On 12/24/12 09:36, Roy Smith wrote:
> I have an integer that I want to encode as a hex string, but I don't 
> want "0x" at the beginning, nor do I want "L" at the end if it happened 
> to be a long.  The result needs to be something I can pass to int(h, 16) 
> to get back my original integer.
> 
> The brute force way works:
> 
>    h = hex(i)
>    assert h.startswith('0x')
>    h = h[2:]
>    if h.endswith('L'):
>        h = h[:-1]
> 
> but I'm wondering if there's some built-in call which gives me what I 
> want directly.  Python 2.7.

Would something like

  h = "%08x" % i

or

  h = "%x" % i

work for you?

-tkc

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#35465

In article <mailman.1256.1356364625.29569.python-list@python.org>,
 Tim Chase <python.list@tim.thechases.com> wrote:

> On 12/24/12 09:36, Roy Smith wrote:
> > I have an integer that I want to encode as a hex string, but I don't 
> > want "0x" at the beginning, nor do I want "L" at the end if it happened 
> > to be a long.  The result needs to be something I can pass to int(h, 16) 
> > to get back my original integer.
> > 
> > The brute force way works:
> > 
> >    h = hex(i)
> >    assert h.startswith('0x')
> >    h = h[2:]
> >    if h.endswith('L'):
> >        h = h[:-1]
> > 
> > but I'm wondering if there's some built-in call which gives me what I 
> > want directly.  Python 2.7.
> 
> Would something like
> 
>   h = "%08x" % i
> 
> or
> 
>   h = "%x" % i
> 
> work for you?

Duh.  Of course.  Thanks.

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#35478

On 2012-12-24 15:58, Tim Chase wrote:
> On 12/24/12 09:36, Roy Smith wrote:
>> I have an integer that I want to encode as a hex string, but I don't
>> want "0x" at the beginning, nor do I want "L" at the end if it happened
>> to be a long.  The result needs to be something I can pass to int(h, 16)
>> to get back my original integer.
>>
>> The brute force way works:
>>
>>    h = hex(i)
>>    assert h.startswith('0x')
>>    h = h[2:]
>>    if h.endswith('L'):
>>        h = h[:-1]
>>
>> but I'm wondering if there's some built-in call which gives me what I
>> want directly.  Python 2.7.
>
> Would something like
>
>    h = "%08x" % i
>
> or
>
>    h = "%x" % i
>
> work for you?
>
Or:

     h = "{:x}".format(i)

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