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Re: Why chunks is not part of the python standard lib?

Started bySerhiy Storchaka <storchaka@gmail.com>
First post2013-05-01 19:19 +0300
Last post2013-05-01 09:30 -0700
Articles 2 — 2 participants

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  Re: Why chunks is not part of the python standard lib? Serhiy Storchaka <storchaka@gmail.com> - 2013-05-01 19:19 +0300
    Re: Why chunks is not part of the python standard lib? Paul Rubin <no.email@nospam.invalid> - 2013-05-01 09:30 -0700

#44596 — Re: Why chunks is not part of the python standard lib?

FromSerhiy Storchaka <storchaka@gmail.com>
Date2013-05-01 19:19 +0300
SubjectRe: Why chunks is not part of the python standard lib?
Message-ID<mailman.1219.1367425160.3114.python-list@python.org>
01.05.13 09:26, Ricardo Azpeitia Pimentel написав(ла):
> After reading How do you split a list into evenly sized chunks in
> Python?
> <http://stackoverflow.com/questions/312443/how-do-you-split-a-list-into-evenly-sized-chunks-in-python>
> and seeing this kind of mistakes happening
> https://code.djangoproject.com/ticket/18972 all the time.
>
> Why is not a |chunks| function in itertools?

Because not every 1 line function needs to be in the standard library.

> |chunks([1,  2,  3,  4,  5],  3)
> # Should return [[1, 2, 3], [4, 5]] or the iterator equivalent.|

def chunks(seq, size):
     return [seq[i: i + size] for i in range(0, len(seq), size)]

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#44597

FromPaul Rubin <no.email@nospam.invalid>
Date2013-05-01 09:30 -0700
Message-ID<7xy5byacis.fsf@ruckus.brouhaha.com>
In reply to#44596
Serhiy Storchaka <storchaka@gmail.com> writes:
> def chunks(seq, size):
>     return [seq[i: i + size] for i in range(0, len(seq), size)]

That's just for lists.  An itertools version would work with arbitrary
iterables.  I've also had to rewrite that function more times than seems
proper.

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