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finditer

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  finditer gintare <g.statkute@gmail.com> - 2014-07-07 00:19 -0700
    Re: finditer Jason Friedman <jsf80238@gmail.com> - 2014-07-07 21:38 -0600

#74080 — finditer

If smbd has time, maybe you could advice how to accomplish this task in faster way.

I have a text = """ word{vb}
wordtransl {vb}

sent1.

sent1trans.

sent2

sent2trans... """

I need to match once wordtransl, and than many times repeating patterns consisting of sent and senttrans.




The way i achieved this goal is for sure not most efficient one:
sw=word # i know the word
stry='\s*'+sw+'\s*.*\{vb\}\n+'
stry=stry+'(?P<Wtrans>.*)\{vb\}\n+'
stryc=re.compile(stry, re.UNICODE)
LtryM=re.search(stryc, linef) #here i find wordtrans

part=re.split(stryc,linef) #here i split search text to obtain part with repeating sent and senttrans

stry2='(?:'
stry2=stry2+'\s*'+sw+'\s*.*\{vb\}\n+'
stry2=stry2+'(?P<Wtrans>.*)\{vb\}\n+'
stry2=stry2+')*'
stry2=stry2+'('
stry2=stry2+'(?P<SVsent>.*)\n+'
stry2=stry2+'(?P<SVtrans>.*)\n+'
stry2=stry2+')'
stryc2=re.compile(stry2, re.UNICODE)
LtryM=re.finditer(stryc2, part[2]) #here i find text pieces consisting sent and sentrans 
for item in LtryM:
	stry3=''
	stry3=stry3+'(?P<SVsent>.*)\n+'
	stry3=stry3+'(?P<SVtrans>.*)\n+'
	stryc3=re.compile(stry3, re.UNICODE)
	LtryM3=re.search(stryc3, item.group()) #here i find sent and senttrans
	print(LtryM3.groupdict())

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#74147

On Mon, Jul 7, 2014 at 1:19 AM, gintare <g.statkute@gmail.com> wrote:
> If smbd has time, maybe you could advice how to accomplish this task in faster way.
>
> I have a text = """ word{vb}
> wordtransl {vb}
>
> sent1.
>
> sent1trans.
>
> sent2
>
> sent2trans... """
>
> I need to match once wordtransl, and than many times repeating patterns consisting of sent and senttrans.

You might try itertools.groupby
(https://docs.python.org/3/library/itertools.html#module-itertools).

text = """ word{vb}
wordtransl {vb}

sent1

sent1trans

sent2

sent2trans
"""

import itertools
import re
result_list = list()
lines = text.split("\n")

for line in lines[:]:
    if line.startswith("sent"):
        break
    lines.pop(0)

def is_start(x):
    pattern = re.compile(r"sent\d+$")
    if re.search(pattern, x):
        return True

for key, mygroup in itertools.groupby(lines, is_start):
    result_list.append(list(mygroup))

print(result_list)

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