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Python Fails to Write to File

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  Python Fails to Write to File cutey Love <cuteywithlove@gmail.com> - 2014-06-18 16:03 -0700
    Re: Python Fails to Write to File Ian Kelly <ian.g.kelly@gmail.com> - 2014-06-18 17:18 -0600
    Re: Python Fails to Write to File Paul McNett <paul@mcnettware.com> - 2014-06-18 16:20 -0700
    Re: Python Fails to Write to File cutey Love <cuteywithlove@gmail.com> - 2014-06-19 00:54 -0700
      Re: Python Fails to Write to File Mark Lawrence <breamoreboy@yahoo.co.uk> - 2014-06-19 09:39 +0100

#73384 — Python Fails to Write to File

I'm trying to write data to a text file

But I'm getting the error:

TypeError: invalid file: <_io.TextIOWrapper 

Code is 

def saveFile():
    file_path = filedialog.asksaveasfile(mode='w', filetypes=[('text files', '.txt')], defaultextension=".txt")
    fo = open(file_path, 'w')
    
    for e in myList:
        fo.write(e)
            
    
    fo.close()

The file is being created if not already present but no data is written

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#73385

On Wed, Jun 18, 2014 at 5:03 PM, cutey Love <cuteywithlove@gmail.com> wrote:
> I'm trying to write data to a text file
>
> But I'm getting the error:
>
> TypeError: invalid file: <_io.TextIOWrapper

Post the full traceback.  By posting only the error message you're
removing useful information.

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#73386

On 6/18/14, 4:03 PM, cutey Love wrote:
> I'm trying to write data to a text file
>
> But I'm getting the error:
>
> TypeError: invalid file: <_io.TextIOWrapper

Always better to err on posting too much context (the entire traceback) 
than too little.


> Code is
>
> def saveFile():
>      file_path = filedialog.asksaveasfile(mode='w', filetypes=[('text files', '.txt')], defaultextension=".txt")
>      fo = open(file_path, 'w')

I used Google (searched on "filedialog.asksaveasfile") to realize that 
you are likely using Tkinter. I then used Google to find out the API for 
filedialog.asksaveasfile() and I found that it returns the ALREADY OPEN 
FILE for you to write to, not the name of the file you are writing to.

Referring to that same documentation, I see there's another function you 
are probably more interested in: filedialog.asksaveasfilename(). Then, 
you can open the file, write to it, and close it and be in control of 
every step. Not sure which is preferable, though, as I have no (recent) 
Tkinter experience.


>
>      for e in myList:
>          fo.write(e)
>
>
>      fo.close()

You should use a context manager to open, write to, and close files. 
Such as:

with open(file_path, 'w') as fo:
     for e in myList:
         fo.write(e)

> The file is being created if not already present but no data is written

filedialog.asksaveasfile() was opening it for you. It was being closed 
automatically when file_path fell out of scope (after the exception 
caused by your fo = open(file_path, 'w') line.

My response was intended to help.
Paul

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#73403

Thank you very much, that fixed it.

On Thursday, June 19, 2014 12:03:43 AM UTC+1, cutey Love wrote:
> I'm trying to write data to a text file
> 
> 
> 
> But I'm getting the error:
> 
> 
> 
> TypeError: invalid file: <_io.TextIOWrapper 
> 
> 
> 
> Code is 
> 
> 
> 
> def saveFile():
> 
>     file_path = filedialog.asksaveasfile(mode='w', filetypes=[('text files', '.txt')], defaultextension=".txt")
> 
>     fo = open(file_path, 'w')
> 
>     
> 
>     for e in myList:
> 
>         fo.write(e)
> 
>             
> 
>     
> 
>     fo.close()
> 
> 
> 
> The file is being created if not already present but no data is written

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#73405

On 19/06/2014 08:54, cutey Love wrote:
> Thank you very much, that fixed it.
>

What do you not understand about top posting and using google groups?

-- 
My fellow Pythonistas, ask not what our language can do for you, ask 
what you can do for our language.

Mark Lawrence

---
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