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Re: datetime.timedelta.replace?

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  Re: datetime.timedelta.replace? Joshua Landau <joshua@landau.ws> - 2013-10-11 18:56 +0100

#56697 — Re: datetime.timedelta.replace?

On 9 October 2013 16:15, Skip Montanaro <skip@pobox.com> wrote:
> Datetime objects have a replace method, but timedelta objects don't.
> If I take the diff of two datetimes and want to zero out the
> microseconds field, is there some way to do it more cleanly than this?
>
> delta = dt1 - dt2
> zero_delta = datetime.timedelta(days=delta.days, seconds=delta.seconds)
>
> I guess that's not bad, but replace() seems cleaner (or at least more
> congruent with datetime objects).

Maybe one of

    delta - datetime.timedelta(0, 0, delta.microseconds)

or

    delta - delta % datetime.timedelta(seconds=1)

is clearer.

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