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| Started by | Arnaud Delobelle <arnodel@gmail.com> |
|---|---|
| First post | 2011-02-11 07:09 +0000 |
| Last post | 2011-02-11 07:09 +0000 |
| Articles | 1 — 1 participant |
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Re: Parameterized functions of no arguments? Arnaud Delobelle <arnodel@gmail.com> - 2011-02-11 07:09 +0000
| From | Arnaud Delobelle <arnodel@gmail.com> |
|---|---|
| Date | 2011-02-11 07:09 +0000 |
| Subject | Re: Parameterized functions of no arguments? |
| Message-ID | <87ei7favyr.fsf@gmail.com> |
Rotwang <sg552@hotmail.co.uk> writes:
> On 11/02/2011 06:19, Paul Rubin wrote:
>> Rotwang<sg552@hotmail.co.uk> writes:
>>> menu = Tkinter.Menu(master, tearoff = 0)
>>> for k in x:
>>> def f(j = k):
>>> [do something that depends on j]
>>> menu.add_command(label = str(k), command = f)
>>>
>>> Still, I'd like to know if there's a more elegant method for creating
>>> a set of functions indexed by an arbitrary list.
>>
>> That is a standard python idiom. These days maybe I'd use partial
>> evaluation:
>>
>> from functools import partial
>>
>> def f(k): whatever...
>>
>> for k in x:
>> menu.add_command(label=str(k), command=partial(f, k))
>
> functools is new to me, I will look into it. Thanks.
>
>
>> the "pure" approach would be something like
>>
>> def f(k): whatever...
>>
>> for k in x:
>> menu.add_command(label=str(k),
>> command=(lambda x: lambda: f(x))(k))
>
> I don't understand why this works. What is the difference between
>
> (lambda x: lambda: f(x))(k)
>
The value of k is bound to the local variable x; If k is changed later,
it doesn't affect the value of x above
Note that you can also write it:
lambda k=k: f(k)
> and
>
> lambda: f(k)
>
> ?
K not being local, If k is changed later, it does affect the above.
--
Arnaud
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