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Groups > comp.lang.python > #97979 > unrolled thread

i want to print next element i liste

Started byellelelet@gmail.com
First post2015-10-28 05:23 -0700
Last post2015-10-29 12:48 +0000
Articles 10 — 6 participants

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  i want to print next element i liste ellelelet@gmail.com - 2015-10-28 05:23 -0700
    Re: i want to print next element i liste darnold <darnold992000@yahoo.com> - 2015-10-28 07:05 -0700
      Re: i want to print next element i liste darnold <darnold992000@yahoo.com> - 2015-10-28 07:16 -0700
    Re: i want to print next element i liste Ellelele Toget <ellelelet@gmail.com> - 2015-10-28 07:34 -0700
      Re: i want to print next element i liste Christian Gollwitzer <auriocus@gmx.de> - 2015-10-28 17:12 +0100
        Re: i want to print next element i liste Ellelele Toget <ellelelet@gmail.com> - 2015-10-28 14:58 -0700
          Re: i want to print next element i liste Ellelele Toget <ellelelet@gmail.com> - 2015-10-28 15:02 -0700
            Re: i want to print next element i liste Larry Hudson <orgnut@yahoo.com> - 2015-10-28 19:12 -0700
              Re: i want to print next element i liste Ellelele Toget <ellelelet@gmail.com> - 2015-10-29 01:55 -0700
                Re: i want to print next element i liste Denis McMahon <denismfmcmahon@gmail.com> - 2015-10-29 12:48 +0000

#97979 — i want to print next element i liste

Fromellelelet@gmail.com
Date2015-10-28 05:23 -0700
Subjecti want to print next element i liste
Message-ID<25e0abea-f1a6-446c-af4e-f01fb5b482f0@googlegroups.com>
L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
for i,w in enumerate(L):
    if L.count(w)>=3:
       order_list.append(i)
       print i,w

 result:
1 book
3 book
5 book
8 book
how can i print "good" then? it comes after last book element.

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#97980

Fromdarnold <darnold992000@yahoo.com>
Date2015-10-28 07:05 -0700
Message-ID<1a678d2e-9bf7-4199-9989-1d88942996b4@googlegroups.com>
In reply to#97979
On Wednesday, October 28, 2015 at 7:23:40 AM UTC-5, Ellelele Toget wrote:
> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
> for i,w in enumerate(L):
>     if L.count(w)>=3:
>        order_list.append(i)
>        print i,w
> 
>  result:
> 1 book
> 3 book
> 5 book
> 8 book
> how can i print "good" then? it comes after last book element.

presumably, L is actually a list of strings.

that aside, your condition on printing a word is that it appears in L three or more times:

>     if L.count(w)>=3:
>        order_list.append(i)
>        print i,w

'book' appears in the list less than three times, so it doesn't satisfy the condition and isn't printed.

HTH,
Don

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#97981

Fromdarnold <darnold992000@yahoo.com>
Date2015-10-28 07:16 -0700
Message-ID<412f85b2-9b0c-462b-a2db-8c55d3136b46@googlegroups.com>
In reply to#97980
On Wednesday, October 28, 2015 at 9:05:59 AM UTC-5, darnold wrote:
> On Wednesday, October 28, 2015 at 7:23:40 AM UTC-5, Ellelele Toget wrote:
> > L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
> > for i,w in enumerate(L):
> >     if L.count(w)>=3:
> >        order_list.append(i)
> >        print i,w
> > 
> >  result:
> > 1 book
> > 3 book
> > 5 book
> > 8 book
> > how can i print "good" then? it comes after last book element.
> 
> presumably, L is actually a list of strings.
> 
> that aside, your condition on printing a word is that it appears in L three or more times:
> 
> >     if L.count(w)>=3:
> >        order_list.append(i)
> >        print i,w
> 
> 'book' appears in the list less than three times, so it doesn't satisfy the condition and isn't printed.
> 
> HTH,
> Don

whoops. that should read:

'good' appears in the list less than three times, so it doesn't satisfy the condition and isn't printed.


sorry for any confusion,
Don

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#97982

FromEllelele Toget <ellelelet@gmail.com>
Date2015-10-28 07:34 -0700
Message-ID<76077a86-40cf-42b0-bace-a8c25c03729e@googlegroups.com>
In reply to#97979
On Wednesday, October 28, 2015 at 1:23:40 PM UTC+1, Ellelele Toget wrote:
> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
> for i,w in enumerate(L):
>     if L.count(w)>=3:
>        order_list.append(i)
>        print i,w
> 
>  result:
> 1 book
> 3 book
> 5 book
> 8 book
> how can i print "good" then? it comes after last book element.
next() function print next element in dictionary but this is a list therefore is there Another function for list like next() or Another codes

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#97983

FromChristian Gollwitzer <auriocus@gmx.de>
Date2015-10-28 17:12 +0100
Message-ID<n0qs11$3v5$1@dont-email.me>
In reply to#97982
Am 28.10.15 um 15:34 schrieb Ellelele Toget:
> On Wednesday, October 28, 2015 at 1:23:40 PM UTC+1, Ellelele Toget wrote:
>> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
>> for i,w in enumerate(L):
>>      if L.count(w)>=3:
>>         order_list.append(i)
>>         print i,w
>>
>>   result:
>> 1 book
>> 3 book
>> 5 book
>> 8 book
>> how can i print "good" then? it comes after last book element.
> next() function print next element in dictionary but this is a list therefore is there Another function for list like next() or Another codes
>

L[i+1]

???

	Christian

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#97987

FromEllelele Toget <ellelelet@gmail.com>
Date2015-10-28 14:58 -0700
Message-ID<f4b6cec8-0404-46ee-bc60-49f721c5cb6e@googlegroups.com>
In reply to#97983
On Wednesday, October 28, 2015 at 5:12:45 PM UTC+1, Christian Gollwitzer wrote:
> Am 28.10.15 um 15:34 schrieb Ellelele Toget:
> > On Wednesday, October 28, 2015 at 1:23:40 PM UTC+1, Ellelele Toget wrote:
> >> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
> >> for i,w in enumerate(L):
> >>      if L.count(w)>=3:
> >>         order_list.append(i)
> >>         print i,w
> >>
> >>   result:
> >> 1 book
> >> 3 book
> >> 5 book
> >> 8 book
> >> how can i print "good" then? it comes after last book element.
> > next() function print next element in dictionary but this is a list therefore is there Another function for list like next() or Another codes
> >
> 
> L[i+1]
> 
> ???
> 
> 	Christian

L=[house, book, pen, book, pencil, book, clock, cat, book, good, write] 
for i, w enumerate(L):
    if L.count(w)>=3:
 print L[i+1]
result:
pen
pencil
Clock
good

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#97988

FromEllelele Toget <ellelelet@gmail.com>
Date2015-10-28 15:02 -0700
Message-ID<0cb60a10-186b-45fb-8170-28003e901921@googlegroups.com>
In reply to#97987
On Wednesday, October 28, 2015 at 10:59:19 PM UTC+1, Ellelele Toget wrote:
> On Wednesday, October 28, 2015 at 5:12:45 PM UTC+1, Christian Gollwitzer wrote:
> > Am 28.10.15 um 15:34 schrieb Ellelele Toget:
> > > On Wednesday, October 28, 2015 at 1:23:40 PM UTC+1, Ellelele Toget wrote:
> > >> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
> > >> for i,w in enumerate(L):
> > >>      if L.count(w)>=3:
> > >>         order_list.append(i)
> > >>         print i,w
> > >>
> > >>   result:
> > >> 1 book
> > >> 3 book
> > >> 5 book
> > >> 8 book
> > >> how can i print "good" then? it comes after last book element.
> > > next() function print next element in dictionary but this is a list therefore is there Another function for list like next() or Another codes
> > >
> > 
> > L[i+1]
> > 
> > ???
> > 
> > 	Christian
> 
> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write] 
> for i, w enumerate(L):
>     if L.count(w)>=3:
>  print L[i+1]
> result:
> pen
> pencil
> Clock
> good

i will only good

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#97989

FromLarry Hudson <orgnut@yahoo.com>
Date2015-10-28 19:12 -0700
Message-ID<sPudnc0nj4EbHazLnZ2dnUU7-a2dnZ2d@giganews.com>
In reply to#97988
On 10/28/2015 03:02 PM, Ellelele Toget wrote:
> On Wednesday, October 28, 2015 at 10:59:19 PM UTC+1, Ellelele Toget wrote:
>> On Wednesday, October 28, 2015 at 5:12:45 PM UTC+1, Christian Gollwitzer wrote:
>>> Am 28.10.15 um 15:34 schrieb Ellelele Toget:
>>>> On Wednesday, October 28, 2015 at 1:23:40 PM UTC+1, Ellelele Toget wrote:
>>>>> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
>>>>> for i,w in enumerate(L):
>>>>>       if L.count(w)>=3:
>>>>>          order_list.append(i)
>>>>>          print i,w
>>>>>
>>>>>    result:
>>>>> 1 book
>>>>> 3 book
>>>>> 5 book
>>>>> 8 book
>>>>> how can i print "good" then? it comes after last book element.

[snip]

>
> i will only good
>
You will have to explain to us what is special about 'good' that makes it different from 
'house', 'pen', 'pencil', 'clock', 'cat' or 'write'.

      -=- Larry -=-

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#97993

FromEllelele Toget <ellelelet@gmail.com>
Date2015-10-29 01:55 -0700
Message-ID<fea1d5fa-e3c8-40f4-9372-669634938718@googlegroups.com>
In reply to#97989
On Thursday, October 29, 2015 at 3:12:49 AM UTC+1, Larry Hudson wrote:
> On 10/28/2015 03:02 PM, Ellelele Toget wrote:
> > On Wednesday, October 28, 2015 at 10:59:19 PM UTC+1, Ellelele Toget wrote:
> >> On Wednesday, October 28, 2015 at 5:12:45 PM UTC+1, Christian Gollwitzer wrote:
> >>> Am 28.10.15 um 15:34 schrieb Ellelele Toget:
> >>>> On Wednesday, October 28, 2015 at 1:23:40 PM UTC+1, Ellelele Toget wrote:
> >>>>> L=[house, book, pen, book, pencil, book, clock, cat, book, good, write]
> >>>>> for i,w in enumerate(L):
> >>>>>       if L.count(w)>=3:
> >>>>>          order_list.append(i)
> >>>>>          print i,w
> >>>>>
> >>>>>    result:
> >>>>> 1 book
> >>>>> 3 book
> >>>>> 5 book
> >>>>> 8 book
> >>>>> how can i print "good" then? it comes after last book element.
> 
> [snip]
> 
> >
> > i will only good
> >
> You will have to explain to us what is special about 'good' that makes it different from 
> 'house', 'pen', 'pencil', 'clock', 'cat' or 'write'.
> 
>       -=- Larry -=-

When the transmitting host receives least three duplicate ACKs from the recipient it assumes the packet was indeed lost in transit and immediately sends a fast retransmission. This fast retransmission is different than a standard retransmission because once it is triggered all other packets being transmitted are queued until it is sent. 

i put all packets in list and after i will find least 3 duplicate packets and it print soon coming next packet, if it is 3 duplicate packets it print 4. packet. if it is 25 duplicate packet it print 26. packet. Algorithm run so:)

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#97998

FromDenis McMahon <denismfmcmahon@gmail.com>
Date2015-10-29 12:48 +0000
Message-ID<n0t4j2$b2m$1@dont-email.me>
In reply to#97993
On Thu, 29 Oct 2015 01:55:51 -0700, Ellelele Toget wrote:

> i put all packets in list and after i will find least 3 duplicate
> packets and it print soon coming next packet, if it is 3 duplicate
> packets it print 4. packet. if it is 25 duplicate packet it print 26.
> packet. Algorithm run so:)

So in a list of things, you want to find the thing that comes after the 
third occurrence of another thing.

Now I think we know what you actually want to do.

This probably isn't the best way to do it, but it seems to work:

#!/usr/bin/python

l = ["house", "book", "pen", "book", "pencil", "book", "clock", "cat", 
"book", "good", "write"]

d = {}

flag = False
for thing in l:
    if flag:
        print thing
        break
    else:
        if thing in d:
            d[thing] = d[thing] + 1
            if d[thing] == 3:
                flag = True
        else:
            d[thing] = 1

-- 
Denis McMahon, denismfmcmahon@gmail.com

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