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Re: subprocess.Popen question

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On Tue, 16 Aug 2011 02:03:50 -0500, Danny Wong (dannwong) wrote:

> 	I'm executing a command which I want to capture the
> standard/stderr output into a file (which I have with the code below),
> but I also want the standard output to go into a variable so I can
> process the information for the next command. Any ideas? Thanks.
> 
> CMD_OUTPUT = subprocess.Popen(COMMAND, stdout=PROJECT_LOGFILE,
> stderr=subprocess.STDOUT)

	CMD_OUTPUT.wait()
	with open(PROJECT_LOGFILE,'r') as f:
	  str = f.read()

If you're going to be writing it to a file anyhow, reading that file is
likely to be faster than the alternatives.

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subprocess.Popen question "Danny Wong (dannwong)" <dannwong@cisco.com> - 2011-08-16 02:03 -0500
  Re: subprocess.Popen question Thomas Rachel <nutznetz-0c1b6768-bfa9-48d5-a470-7603bd3aa915@spamschutz.glglgl.de> - 2011-08-16 11:10 +0200
  Re: subprocess.Popen question Nobody <nobody@nowhere.com> - 2011-08-16 12:26 +0100

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