Re: opening a file

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From	Nobody <nobody@nowhere.com>
Subject	Re: opening a file
Date	Mon, 20 Jun 2011 11:01:19 +0100
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On Sun, 19 Jun 2011 23:00:38 -0700, Tim Hanson wrote:

> This works:
> infile=open('/foo/bar/prog/py_modules/this_is_a_test','r')
> 
> This doesn't:
> infile=open('~/prog/py_modules/this_is_a_test','r')
> 
> Can't I work with files using Unix expressions?

The argument is treated literally, just like C's fopen() etc. If you want
substitions, you have to perform them explicitly, e.g.:

infile=open(os.path.expanduser('~/prog/py_modules/this_is_a_test'),'r')

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opening a file Tim Hanson <tjhanson@yahoo.com> - 2011-06-19 23:00 -0700
  Re: opening a file Nobody <nobody@nowhere.com> - 2011-06-20 11:01 +0100

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