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Re: use of index (beginner's question)

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On Thu, 28 Apr 2011 01:49:33 +0100, Chris Angelico <rosuav@gmail.com>
wrote:

> On Thu, Apr 28, 2011 at 10:42 AM, Rusty Scalf <iai-gis@sonic.net> wrote:
>> list1 = ['pig', 'horse', 'moose']
>> list2 =  ['62327', '49123', '79115']
>> n = 2
>> s2 = "list" + `n`
>> a = s2[list1.index('horse')]
>> print a
>
> s2 is a string with the value "list2"; this is not the same as the
> variable list2. You could use eval to convert it, but you'd do better
> to have a list of lists:
>
> lists = [
>  ['pig', 'horse', 'moose']
>  ['62327', '49123', '79115']
> ]
>
> Then you could use:
> n = 2
> a = lists[n][list1.index('horse')]

*cough* I think you mean

n = 1
a = lists[n][list[0].index('horse')]

The alternative would be to have a dictionary of lists:

lists = {
     "list1": ['pig', 'horse', 'moose'],
     "list2": ['62327', '49123', '79115']
}

n = 2
s2 = "list" + str(n)
a = lists[s2][lists["list1"].index('horse')]

Both of these can be made less ugly if the list you want to index into
isn't one of the lists you might want to look up, but that's just a detail.

-- 
Rhodri James *-* Wildebeest Herder to the Masses

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Re: use of index (beginner's question) Chris Angelico <rosuav@gmail.com> - 2011-04-28 10:49 +1000
  Re: use of index (beginner's question) Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2011-04-28 03:23 +0200
    Re: use of index (beginner's question) Chris Rebert <clp2@rebertia.com> - 2011-04-27 18:39 -0700
    Re: use of index (beginner's question) Chris Angelico <rosuav@gmail.com> - 2011-04-28 11:45 +1000
      Re: use of index (beginner's question) Iain King <iainking@gmail.com> - 2011-04-28 01:13 -0700
    Re: use of index (beginner's question) Algis Kabaila <akabaila@pcug.org.au> - 2011-04-28 13:32 +1000
      Re: use of index (beginner's question) Graeme Glass <graemeglass@gmail.com> - 2011-04-28 02:26 -0700
  Re: use of index (beginner's question) "Rhodri James" <rhodri@wildebst.demon.co.uk> - 2011-04-28 22:05 +0100

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