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Groups > comp.lang.python > #95431
| From | Fabien <fabien.maussion@gmail.com> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: Python 3 sort() problem |
| Date | 2015-08-17 16:12 +0200 |
| Organization | Aioe.org NNTP Server |
| Message-ID | <mqsq4l$bq2$1@speranza.aioe.org> (permalink) |
| References | <mailman.58.1439820096.4764.python-list@python.org> |
On 08/17/2015 01:42 PM, Владислав wrote: > x = [1, 2, 4, 2, 1, 3] > x = list(set(x)).sort() > print(x) /# output: None/ > > I know that sort() returns None, but I guess that it would be returned x > that was sorted. Why so? If sort() returns None, than the following: x = list(set(x)).sort() is equivalent to writing: x = None So I don't really understand your question, I'm sorry... Cheers, Fabien
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Re: Python 3 sort() problem Fabien <fabien.maussion@gmail.com> - 2015-08-17 16:12 +0200
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