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Groups > comp.lang.python > #44057

Re: List Count

Date 2013-04-22 08:51 -0400
From Dave Angel <davea@davea.name>
Subject Re: List Count
References <sridnffI6YhxuOjMnZ2dnUVZ7tSdnZ2d@brightview.co.uk>
Newsgroups comp.lang.python
Message-ID <mailman.907.1366635127.3114.python-list@python.org> (permalink)

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On 04/22/2013 07:58 AM, Blind Anagram wrote:
> I would be grateful for any advice people can offer on the fastest way
> to count items in a sub-sequence of a large list.
>
> I have a list of boolean values that can contain many hundreds of
> millions of elements for which I want to count the number of True values
> in a sub-sequence, one from the start up to some value (say hi).
>
> I am currently using:
>
>     sieve[:hi].count(True)
>
> but I believe this may be costly because it copies a possibly large part
> of the sieve.
>
> Ideally I would like to be able to use:
>
>     sieve.count(True, hi)
>
> where 'hi' sets the end of the count but this function is, sadly, not
> available for lists.
>
> The use of a bytearray with a memoryview object instead of a list solves
> this particular problem but it is not a solution for me as it creates
> more problems than it solves in other aspects of the program.
>
> Can I assume that one possible solution would be to sub-class list and
> create a C based extension to provide list.count(value, limit)?
>
> Are there any other solutions that will avoid copying a large part of
> the list?
>

Instead of using the default slice notation, why not use 
itertools.islice() ?

Something like  (untested):

import itertools

it = itertools.islice(sieve, 0, hi)
sum(itertools.imap(bool, it))

I only broke it into two lines for clarity.  It could also be:

sum(itertools.imap(bool, itertools.islice(sieve, 0, hi)))

If you're using Python 3.x, say so, and I'm sure somebody can simplify 
these, since in Python 3, many functions already produce iterators 
instead of lists.


-- 
DaveA

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Thread

List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 12:58 +0100
  Re: List Count Dave Angel <davea@davea.name> - 2013-04-22 08:51 -0400
    Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 14:03 +0100
    Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 14:03 +0100
  Re: List Count Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-04-22 13:13 +0000
    Re: List Count Skip Montanaro <skip@pobox.com> - 2013-04-22 08:57 -0500
    Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 15:15 +0100
      Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-22 16:14 +0100
        Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 16:50 +0100
          Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-22 17:06 +0100
            Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 17:38 +0100
              Re: List Count Skip Montanaro <skip@pobox.com> - 2013-04-22 12:48 -0500
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 20:22 +0100
              Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-22 21:18 +0100
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 22:25 +0100
                Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-23 00:06 +0100
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 07:45 +0100
                Re: List Count Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-04-22 23:28 +0000
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 08:00 +0100
              Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-22 22:03 +0100
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 22:32 +0100
                Re: List Count Dave Angel <davea@davea.name> - 2013-04-22 21:47 -0400
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 08:02 +0100
            Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 17:38 +0100
        Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-22 16:50 +0100
      Re: List Count Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-04-22 23:01 +0000
        Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 08:05 +0100
          Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-23 12:08 +0100
            Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 12:45 +0100
              Re: List Count Terry Jan Reedy <tjreedy@udel.edu> - 2013-04-23 15:01 -0400
          Re: List Count Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-04-23 14:49 +0000
            Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 17:57 +0100
              Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-23 18:45 +0100
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 19:30 +0100
                Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-23 20:16 +0100
              Re: List Count Terry Jan Reedy <tjreedy@udel.edu> - 2013-04-23 16:00 -0400
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-23 21:41 +0100
              Re: List Count Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-04-23 21:38 +0100
              Re: List Count Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-04-24 01:59 +0000
                Re: List Count Blind Anagram <blindanagram@nowhere.org> - 2013-04-24 10:01 +0100
  Re: List Count Peter Otten <__peter__@web.de> - 2013-04-22 15:22 +0200
  Re: List Count 88888 Dihedral <dihedral88888@googlemail.com> - 2013-04-22 06:36 -0700

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