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datetime.timedelta.replace?

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Datetime objects have a replace method, but timedelta objects don't.
If I take the diff of two datetimes and want to zero out the
microseconds field, is there some way to do it more cleanly than this?

delta = dt1 - dt2
zero_delta = datetime.timedelta(days=delta.days, seconds=delta.seconds)

I guess that's not bad, but replace() seems cleaner (or at least more
congruent with datetime objects).

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datetime.timedelta.replace? Skip Montanaro <skip@pobox.com> - 2013-10-09 10:15 -0500

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