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Re: convert output to list(and nested dictionary)

From Peter Otten <__peter__@web.de>
Subject Re: convert output to list(and nested dictionary)
Date 2015-07-22 19:41 +0200
Organization None
References <CAKoJ+qB7mLX+tLAqsO=nSocjVLtLn+TCWZ34z8YVFCKKt10ntQ@mail.gmail.com> <CAB_tDZyB+mCg9yWg9oG0-OL-NHVfCSifkMrD0x3k4LPNx-dhNw@mail.gmail.com> <CAKoJ+qCzMetyyqC-2rg0KB2kmFdVeNkVj053OYeXn9meZ1FJxQ@mail.gmail.com> <CAKoJ+qDp5ii8o1L4ZvimMNyr5Bgm-DBnNy9E5XzB4r_oZY4Ngg@mail.gmail.com>
Newsgroups comp.lang.python
Message-ID <mailman.877.1437586910.3674.python-list@python.org> (permalink)

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max scalf wrote:

> I was able to solve the above problem i listed with the following...please
> let me know if that is the correct way of doing this...or i am way off?
> 
> >>> for sg in sgs:
>     for rule in sg.rules:
>         st = sg, sg.id, "inbound:", rule, " source:", rule.grants
>         s = str(st).replace(","," ")
>         #print s
>         get_data(s)
> 
> 
> {'cidr': 'sg-e632d982-995635159130', 'port': 'None', 'proto': '1'}
> {'cidr': '67.184.225.222/32', 'port': '22', 'proto': 'tcp'}
> {'cidr': '10.0.2.10/32', 'port': '1024', 'proto': 'tcp'}
> {'cidr': '24.12.30.198/32', 'port': '80', 'proto': 'tcp'}
> {'cidr': '10.0.2.10/32', 'port': '138', 'proto': 'udp'}
> {'cidr': '24.12.30.198/32', 'port': '53', 'proto': 'udp'}
> {'cidr': '0.0.0.0/0', 'port': '30015', 'proto': 'tcp'}
> {'cidr': '10.0.2.10/32', 'port': '', 'proto': 'icmp'}

As Chris hinted -- that's the wrong approach. You should instead look at the 
attributes. What does

for sg in sgs:
    print "attributes of sg", dir(sg)
    for rule in sg.rules:
        print "attributes of rule", dir(rule)
        break
    break

print? You should be able to determine the names of the interesting stuff 
from that. If not, try again with vars() instead of dir(), or, the horror!, 
see if you can find some documentation.

Then build the dicts from these attributes, e. g.

result = []
for sg in sgs:
    for rule in sg.rules:
        result.append(dict(cidr=sg.foo, port=rule.bar, proto=rule.baz))
print result

It should be obvious that foo, bar, baz are not the correct attribute names, 
they are placeholders to convey the idea.

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Re: convert output to list(and nested dictionary) Peter Otten <__peter__@web.de> - 2015-07-22 19:41 +0200

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