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| Date | Wed, 29 Apr 2015 09:14:59 -0400 |
| From | Dave Angel <davea@davea.name> |
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| Subject | Re: implicitly concats of adjacent strings does not work with format |
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Show key headers only | View raw
On 04/29/2015 08:42 AM, Cecil Westerhof wrote:
> I have the folowing print statements:
> print(
> 'Calculating fibonacci_old, fibonacci_memoize and '
> 'fibonacci_memoize once for {0} '.format(large_fibonacci))
>
>
> print(
> 'Calculating fibonacci_old, fibonacci_memoize and '
> 'fibonacci_memoize once for {0} '.format(large_fibonacci) +
> 'to determine speed increase')
>
> print(
> 'Calculating fibonacci_old, fibonacci_memoize and '
> 'to determine speed increase'
> 'fibonacci_memoize once for {0} '.format(large_fibonacci))
>
>
> print(
> 'Calculating fibonacci_old, fibonacci_memoize and '
> 'fibonacci_memoize once for {0} '.format(large_fibonacci)
> 'to determine speed increase')
>
> The first three work, but the last gives:
> 'to determine speed increase')
> ^
> SyntaxError: invalid syntax
>
> Not very important, because I can use the second one, but I was just
> wondering why it goes wrong.
>
Adjacent string literals are concatenated. But once you've called a
method (.format()) on that literal, you now have an expression, not a
string literal.
You could either change the last line to
+ 'to determine speed increase')
or you could concatenate all the strings before calling the format method:
print(
'Calculating fibonacci_old, fibonacci_memoize and '
'fibonacci_memoize once for {0} '
'to determine speed increase' .format(large_fibonacci))
Something you may not realize is that the addjacent-concatenation occurs
at compile time, so your third example could be transformed from:
print(
'Calculating fibonacci_old, fibonacci_memoize and '
'to determine speed increase'
'fibonacci_memoize once for {0} '.format(large_fibonacci))
to:
print(
'Calculating fibonacci_old, fibonacci_memoize and '
'to determine speed increase'
'fibonacci_memoize once for {0}'
' '.format(large_fibonacci))
All three literals are combined before format() is called. Knowing this
could be vital if you had {} elsewhere in the 9single) literal.
--
DaveA
Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread
implicitly concats of adjacent strings does not work with format Cecil Westerhof <Cecil@decebal.nl> - 2015-04-29 14:42 +0200
Re: implicitly concats of adjacent strings does not work with format Dave Angel <davea@davea.name> - 2015-04-29 09:14 -0400
Re: implicitly concats of adjacent strings does not work with format Cecil Westerhof <Cecil@decebal.nl> - 2015-04-29 16:40 +0200
Re: implicitly concats of adjacent strings does not work with format Mark Lawrence <breamoreboy@yahoo.co.uk> - 2015-04-29 17:04 +0100
Re: implicitly concats of adjacent strings does not work with format Cecil Westerhof <Cecil@decebal.nl> - 2015-04-29 19:08 +0200
Re: implicitly concats of adjacent strings does not work with format Mark Lawrence <breamoreboy@yahoo.co.uk> - 2015-04-29 21:51 +0100
Re: implicitly concats of adjacent strings does not work with format Cecil Westerhof <Cecil@decebal.nl> - 2015-04-29 23:51 +0200
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