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Groups > comp.lang.python > #69148
| From | Ben Finney <ben+python@benfinney.id.au> |
|---|---|
| Subject | Re: datetime |
| Date | 2014-03-27 08:36 +1100 |
| References | <CABLWypNDCGcojSWR_Dp9NKJtEQH9cshgTZoY=7cm6Ye9_Ai73g@mail.gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.8591.1395869819.18130.python-list@python.org> (permalink) |
Victor Engle <victor.engle@gmail.com> writes:
> It would be convenient if datetime.date.today() accepted an argument
> as an offset from today, like datetime.date.today(-1). Is there an
> easy way to do this with datetime?
The types defined in ‘datetime’ can perform calendar arithmetic::
import datetime
today = datetime.date.today()
one_day = datetime.timedelta(days=1)
yesterday = today - one_day
tomorrow = today + one_day
<URL:http://docs.python.org/3/library/datetime.html#datetime.timedelta>
--
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Ben Finney
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Re: datetime Ben Finney <ben+python@benfinney.id.au> - 2014-03-27 08:36 +1100
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