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| References | <CACwCsY71moXc+72Y5CT6B2+_8d8cPNFyq7zG49STYWcZ5gfkEA@mail.gmail.com> <CAPTjJmrGj-aPYj7pS6zFcobRVj-OpM6oHq9q2OgC-RF+gG1b-A@mail.gmail.com> <CALwzidnj=OKw906wLLyaPZjAzDusdGCdwuOKR65mkQKOq=0MuA@mail.gmail.com> |
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| Date | 2015-09-23 09:06 +1000 |
| Subject | Re: sort help |
| From | Chris Angelico <rosuav@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.77.1442963207.28679.python-list@python.org> (permalink) |
On Wed, Sep 23, 2015 at 9:02 AM, Ian Kelly <ian.g.kelly@gmail.com> wrote: > On Tue, Sep 22, 2015 at 4:55 PM, Chris Angelico <rosuav@gmail.com> wrote: >> The Python list.sort() method is guaranteed to be >> stable. I can't find a comparable guarantee for sorted() > > https://docs.python.org/3.5/library/functions.html#sorted Right, sorry. Since all I looked at was its docstring, I should have said so :) So, yep, sorted() is guaranteed stable too, and that would be the easiest way to subsort something. ChrisA
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Re: sort help Chris Angelico <rosuav@gmail.com> - 2015-09-23 09:06 +1000
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