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Re: suggestions, comments on an "is_subdict" test

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On 22/04/2011 15:57, Irmen de Jong wrote:
> On 22-4-2011 15:55, Vlastimil Brom wrote:
>> Hi all,
>> I'd like to ask for comments or advice on a simple code for testing a
>> "subdict", i.e. check whether all items of a given dictionary are
>> present in a reference dictionary.
>> Sofar I have:
>>
>> def is_subdict(test_dct, base_dct):
>>      """Test whether all the items of test_dct are present in base_dct."""
>>      unique_obj = object()
>>      for key, value in test_dct.items():
>>          if not base_dct.get(key, unique_obj) == value:
>>              return False
>>      return True
>>
>> I'd like to ask for possibly more idiomatic solutions, or more obvious
>> ways to do this. Did I maybe missed some builtin possibility?
>
>
> I would use:
>
> test_dct.items()<= base_dct.items()
>
In Python 2:

 >>> test_dct = {"foo": 0, "bar": 1}
 >>> base_dct = {"foo": 0, "bar": 1, "baz": 2}
 >>>
 >>> test_dct.items() <= base_dct.items()
False

In Python 3:

 >>> test_dct = {"foo": 0, "bar": 1}
 >>> base_dct = {"foo": 0, "bar": 1, "baz": 2}
 >>> test_dct.items() <= base_dct.items()
True

YMMV

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suggestions, comments on an "is_subdict" test Vlastimil Brom <vlastimil.brom@gmail.com> - 2011-04-22 15:55 +0200
  Re: suggestions, comments on an "is_subdict" test Irmen de Jong <irmen.NOSPAM@xs4all.nl> - 2011-04-22 16:57 +0200
    Re: suggestions, comments on an "is_subdict" test MRAB <python@mrabarnett.plus.com> - 2011-04-22 16:18 +0100
      Re: suggestions, comments on an "is_subdict" test Raymond Hettinger <python@rcn.com> - 2011-04-23 00:23 -0700
    Re: suggestions, comments on an "is_subdict" test Paul Rubin <no.email@nospam.invalid> - 2011-04-23 00:26 -0700

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