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| From | Ned Batchelder <ned@nedbatchelder.com> |
| Subject | Re: Why is the interpreter is returning a 'reference'? |
| Date | Mon, 17 Feb 2014 12:08:34 -0500 |
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On 2/17/14 12:00 PM, Nir wrote:
>>>> k = ['hi','boss']
>>>>
>>>> k
> ['hi', 'boss']
>>>> k= [s.upper for s in k]
>>>> k
> [<built-in method upper of str object at 0x00000000021B2AF8>, <built-in method upper of str object at 0x0000000002283F58>]
>
> Why doesn't the python interpreter just return
> ['HI, 'BOSS'] ?
>
> This isn't a big deal, but I am just curious as to why it does this.
>
You have to invoke s.upper, with parens:
k = [s.upper() for s in k]
In Python, a function or method is a first-class object, so "s.upper" is
a reference to the method, "s.upper()" is the result of calling the method.
--
Ned Batchelder, http://nedbatchelder.com
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Why is the interpreter is returning a 'reference'? Nir <nirchernia@gmail.com> - 2014-02-17 09:00 -0800 Re: Why is the interpreter is returning a 'reference'? emile <emile@fenx.com> - 2014-02-17 09:08 -0800 Re: Why is the interpreter is returning a 'reference'? Joel Goldstick <joel.goldstick@gmail.com> - 2014-02-17 12:08 -0500 Re: Why is the interpreter is returning a 'reference'? Ned Batchelder <ned@nedbatchelder.com> - 2014-02-17 12:08 -0500 Re: Why is the interpreter is returning a 'reference'? Marko Rauhamaa <marko@pacujo.net> - 2014-02-17 19:09 +0200 Re: Why is the interpreter is returning a 'reference'? Zachary Ware <zachary.ware+pylist@gmail.com> - 2014-02-17 11:14 -0600 Re: Why is the interpreter is returning a 'reference'? John Gordon <gordon@panix.com> - 2014-02-17 19:17 +0000
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