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Fwd: Sorting dictionary by datetime value

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---------- Forwarded message ----------
From: Igor Korot <ikorot01@gmail.com>
Date: Sat, Feb 8, 2014 at 12:25 AM
Subject: Re: Sorting dictionary by datetime value
To: Chris Angelico <rosuav@gmail.com>


Chris,


On Fri, Feb 7, 2014 at 11:58 PM, Chris Angelico <rosuav@gmail.com> wrote:

> On Sat, Feb 8, 2014 at 6:53 PM, Igor Korot <ikorot01@gmail.com> wrote:
> > Chris,
> >
> > On Fri, Feb 7, 2014 at 11:09 PM, Chris Angelico <rosuav@gmail.com>
> wrote:
> >> On Sat, Feb 8, 2014 at 6:06 PM, Igor Korot <ikorot01@gmail.com> wrote:
> >>>>>> sorted(a.items(), key=a.get)
> >>> [('1', datetime.datetime(2012, 12, 28, 12, 15, 30, 100)), ('3',
> datetime.datetim
> >>> e(2012, 12, 28, 12, 16, 44, 100)), ('2', datetime.datetime(2012, 12,
> 28, 12, 17,
> >>>  29, 100))]
> >>>>>>
> >>>
> >>> However, trying to do the same thing from the script does not sort the
> >>> dictionary:
> >>>
> >>> sorted(my_dict.items(), key=my_dict.get, reverse=False)
> >>> for key, value in my_dict.items():
> >>>      print value, key
> >>>
> >>> the dictionary prints with unsorted items.
> >>
> >> The sorted() function returns a sorted list. You're then going back to
> >> the original dictionary. Instead, just iterate over the sorted items:
> >>
> >> items = sorted(my_dict.items(), key=my_dict.get, reverse=False)
> >> for key, value in items:
> >>     print value, key
> >
> > Still does not work. It prints:
> >
> > =======
> > DATE TIME - EVENT
> > 058f63666438&0  - Instance ID
> > Original values
> > 2013-11-15 15:42:27.000499 User Datetime
> > 2013-07-14 16:42:18.000637 Property Keys
> > 2013-11-15 15:42:17.000938 Volume Device
> > 2013-07-14 16:42:22.000276 Last Modify Reg Times 1
> > Sorted values
> > 2013-11-15 15:42:27.000499 User Datetime
> > 2013-07-14 16:42:18.000637 Property Keys
> > 2013-11-15 15:42:17.000938 Volume Device
> > 2013-07-14 16:42:22.000276 Last Modify Reg Times 1
> >
> > Code is as follows:
> >
> > sorted_items = sorted(my_dict.items(), key=my_dict.get, reverse=False)
> > print row[19], " - Instance ID"
> > print "Original values"
> > for key, value in my_dict.items():
> >      print value, key
> > print "Sorted values"
> > for key, value in sorted_items:
> >      print value, key
> >
> > Thank you.
>
> Assuming you sent that privately only by mistake - hope you don't mind
> me responding on-list.
>
> The problem here is actually your key function. my_dict.items()
> returns a series of two-item tuples, none of which exists in your
> dictionary; so you're actually sorting [None, None, None], which isn't
> very useful.
>
> Try this:
>
> sorted_items = sorted(my_dict.keys(), key=my_dict.get)
> for key in sorted_items:
>     print my_dict[key], key
>

This code fail.
sorted_item is a list of tuples. And so iterating the list in the for loop
I will get a tuple.
It probably should be:

for key[1] in sorted_items:

Let me try that.

Thank you.


>
> Note that reverse=False is the default, so you don't need to specify that.
>
> ChrisA
> --
> https://mail.python.org/mailman/listinfo/python-list
>

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Fwd: Sorting dictionary by datetime value Igor Korot <ikorot01@gmail.com> - 2014-02-08 00:25 -0800

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