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| Date | Tue, 13 Mar 2012 15:54:20 +0000 |
| From | James Elford <fil.oracle@gmail.com> |
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| Subject | Re: concatenate function |
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On 13/03/12 14:35, ferreirafm wrote: > Hi List, > I've coded three functions that I would like to concatenate. I mean, run > them one after another. The third function depends on the results of the > second function, which depends on the results of the first one. When I call > one function after another, python runs them at the same time causing > obvious errors messages. I've tried to call one of them from inside another > but no way. Any clues are appreciated. > Complete code goes here: > http://ompldr.org/vZDB4OQ Do you think you could provide a much shorter example to illustrate what you need? In general, when you want to run one function on the result of another, you can do something like: <<< def increment_all(l); ... return [i+1 for i in l] <<< increment_all(increment_all(range(3)) [2, 3, 4] Here we apply the function increment_all to the result of the function increment_all. If you are talking about the "results" of each function in terms of it mutating an object, and then the next function mutating the same object in a (possibly) different way, then calling the functions in order will do what you want. l = [0, 3, 5, 2] l.append(10) # [0, 3, 5, 2, 10] l.sort() # [0, 2, 3, 5, 10] l.append(3) # [0, 2, 3, 5, 10, 3] James > > > > -- > View this message in context: http://python.6.n6.nabble.com/concatenate-function-tp4574176p4574176.html > Sent from the Python - python-list mailing list archive at Nabble.com.
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Re: concatenate function James Elford <fil.oracle@gmail.com> - 2012-03-13 15:54 +0000
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