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Groups > comp.lang.python > #29016
| From | Peter Otten <__peter__@web.de> |
|---|---|
| Subject | Re: confused in decorate and closure |
| Date | 2012-09-13 08:32 +0200 |
| Organization | None |
| References | <CALZWPGgYJqBJF3BKw=vkYA==69-W+UWtiQyQA9Sk_UPEsmC-rQ@mail.gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.594.1347517951.27098.python-list@python.org> (permalink) |
月忧茗 wrote: > HI, I have some test code: > > > def num(num): > def deco(func): > def wrap(*args, **kwargs): > inputed_num = num > return func(*args, **kwargs) > return wrap > return deco > > > @num(5) > def test(a): > return a + inputed_num > > print test(1) > > > when run this code, I got an error shows that 'inputed_num' is not > defined > > My question is: > In wrap function, is there not a closure that func can got 'inputed_num' > ? > > > > Anyway, If not, how should I do to got my aim: Initialize some value, > and use this value directly in the main function. Variable scopes are determined statically. In > def test(a): > return a + inputed_num "inputed_num" is a global variable. > @num(5) is not a macro, but a shortcut that tells Python to execute test = num(5)(test) and thus does not change the scopes. To get the desired effect you have to turn "inputed_num" into an explicit function argument, for example: >>> def num(n): ... def deco(f): ... def wrap(*args, **kw): ... return f(n, *args, **kw) ... return wrap ... return deco ... >>> @num(42) ... def test(n, a): ... return n + a ... >>> test(1) 43
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Re: confused in decorate and closure Peter Otten <__peter__@web.de> - 2012-09-13 08:32 +0200
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