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| From | emile <emile@fenx.com> |
| Subject | Re: Modifying the default argument of function |
| Date | Tue, 21 Jan 2014 11:20:15 -0800 |
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Function defs with mutable arguments hold a reference to the mutable container such that all invocations access the same changeable container. To get separate mutable default arguments, use: def f(x=None): if x is None: x=[2,3] Emile On 01/21/2014 11:11 AM, Mû wrote: > Hi everybody, > > A friend of mine asked me a question about the following code: > > [code] > def f(x=[2,3]): > x.append(1) > return x > > print(f()) > print(f()) > print(f()) > [/code] > > The results are [2, 3, 1], [2, 3, 1, 1] and [2, 3, 1, 1, 1]. > > The function acts as if there were a global variable x, but the call of > x results in an error (undefined variable). I don't understand why the > successive calls of f() don't return the same value: indeed, I thought > that [2,3] was the default argument of the function f, thus I expected > the three calls of f() to be exactly equivalent. > > I'm don't know much about python, does anybody have a simple explanation > please? >
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Modifying the default argument of function Mû <mu--@melix.net> - 2014-01-21 20:11 +0100
Re: Modifying the default argument of function Chris Angelico <rosuav@gmail.com> - 2014-01-22 06:19 +1100
Re: Modifying the default argument of function Mû <mu--@melix.net> - 2014-01-21 20:36 +0100
Re: Modifying the default argument of function Chris Angelico <rosuav@gmail.com> - 2014-01-22 06:46 +1100
Re: Modifying the default argument of function Asaf Las <roegltd@gmail.com> - 2014-01-21 16:30 -0800
Re: Modifying the default argument of function Steve Jones <steve@secretvolcanobase.org> - 2014-01-21 19:19 +0000
Re: Modifying the default argument of function emile <emile@fenx.com> - 2014-01-21 11:20 -0800
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