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| From | Peter Otten <__peter__@web.de> |
| Subject | Re: numpy.where() and multiple comparisons |
| Date | Sat, 18 Jan 2014 09:50 +0100 |
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John Ladasky wrote: > On Friday, January 17, 2014 6:16:28 PM UTC-8, duncan smith wrote: > >> >>> a = np.arange(10) >> >>> c = np.where((2 < a) & (a < 7)) >> >>> c >> (array([3, 4, 5, 6]),) > > Nice! Thanks! > > Now, why does the multiple comparison fail, if you happen to know? 2 < a < 7 is equivalent to 2 < a and a < 7 Unlike `&` `and` cannot be overridden (*), so the above implies that the boolean value bool(2 < a) is evaluated. That triggers the error because the numpy authors refused to guess -- and rightly so, as both implementable options would be wrong in a common case like yours. (*) I assume overriding would collide with short-cutting of boolean expressions.
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numpy.where() and multiple comparisons John Ladasky <john_ladasky@sbcglobal.net> - 2014-01-17 17:51 -0800
Re: numpy.where() and multiple comparisons duncan smith <buzzard@invalid.invalid> - 2014-01-18 02:16 +0000
Re: numpy.where() and multiple comparisons John Ladasky <john_ladasky@sbcglobal.net> - 2014-01-17 20:00 -0800
Re: numpy.where() and multiple comparisons Peter Otten <__peter__@web.de> - 2014-01-18 09:50 +0100
Re: numpy.where() and multiple comparisons Tim Roberts <timr@probo.com> - 2014-01-18 13:20 -0800
'and' is not exactly an 'operator' (was Re: numpy.where() and multiple comparisons) Terry Reedy <tjreedy@udel.edu> - 2014-01-18 19:12 -0500
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